private List<Movie> movieItems = null;
public List<Movie> getMovieItems() {
final int first = 0;
if (movieItems == null) {
getPagingInfo();
movieItems = jpaController.findRange(new int[]{pagingInfo.getFirstItem(), pagingInfo.getFirstItem() + pagingInfo.getBatchSize()});
Collections.sort(movieItems, new Comparator(){
public int compare (Object o1, Object o2){
Date d1 = movieItems.get(((Movie)o1).getMovieId()).getDate();
Date d2 = movieItems.get(((Movie)o2).getMovieId()).getDate();
if(d1.before(d2)){
movieItems.set(1, (Movie)o1);
movieItems.set(2, (Movie)o2);
}
return first;
}
});
}
return movieItems;
}
jpaController 正在带回 4 部电影并为我提供以下内容
java.lang.ArrayIndexOutOfBoundsException: Array index out of range: 4 at java.util.Vector.get(Vector.java:694) at entitybeans.jsf.PeliculaController$1.compare(PeliculaController.java:260) at java.util.Arrays.mergeSort(Arrays.java:1270) at java.util.Arrays.sort(Arrays.java:1210) at java.util.Collections.sort(Collections.java:159) at entitybeans.jsf.PeliculaController.getPeliculaItems(PeliculaController.java:257) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at javax.el.BeanELResolver.getValue(BeanELResolver.java:302) at javax.el.CompositeELResolver.getValue(CompositeELResolver.java:175) at com.sun.faces.el.FacesCompositeELResolver.getValue(FacesCompositeELResolver.java:72) at com.sun.el.parser.AstValue.getValue(AstValue.java:116) at com.sun.el.parser.AstValue.getValue(AstValue.java:163)....
最佳答案
在您的compare
方法中,o1
和o2
已经是movieItems
列表中的元素。所以,你应该这样做:
Collections.sort(movieItems, new Comparator<Movie>() {
public int compare(Movie m1, Movie m2) {
return m1.getDate().compareTo(m2.getDate());
}
});
关于java - 如何按日期对对象列表进行排序(java 集合,List<Object>),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/5207029/