Javascript - 解释数组的问题

Question

我正在尝试创建一个机器人来解释数组(exp 表)并返回两个级别之间的 exp 差异。

我仍然是 JavaScript 的新手，所以我确信它在我的代码中，我尝试了 array.find、array[x] 的各种组合并将公式移动到变量中。我就是想不通。

var xparray = [1, 0, 2, 300, 3, 900, 4, 2000, 5, 3700, 6, 6000, 7, 10200, 8, 16200, 9, 23550, 10, 33480, 11, 45280, 12, 60880, 13, 80480, 14, 104180, 15, 130580, 16, 161080, 17, 196480, 18, 236980, 19, 282680, 20, 333680, 21, 390280, 22, 454180, 23, 525580, 24, 604680, 25, 691780, 26, 786980, 27, 896780, 28, 1021580, 29, 1161780, 30, 1317680, 31, 1480180, 32, 1656080, 33, 1845680, 34, 2049180, 35, 2267080, 36, 2499400, 37, 2749300, 38, 3017100, 39, 3303300, 40, 3608200, 41, 3932200, 42, 4272400, 43, 4629200, 44, 5002900, 45, 5393700, 46, 5801900, 47, 6239500, 48, 6707000, 49, 7205000, 50, 7734000, 51, 8598000, 52, 9656400, 53, 10923600, 54, 12478800, 55, 14350800, 56, 16568400, 57, 19160400, 58, 22155600, 59, 25582800, 60, 29470800, 61, 33940800, 62, 38813800, 63, 44129800, 64, 49938800, 65, 56302800, 66, 63297800, 67, 71019800, 68, 79594800, 69, 89187800, 70, 100013800, 71, 112462800, 72, 126343800, 73, 141899800, 74, 159398400, 75, 179148400, 76, 201478400, 77, 226818400, 78, 255468400, 79, 288218400, 80, 325868400];


var tn = (String(message).length);
// !xp 40 60
var a = (String(message).length)-3;
var b = (String(message).length)-3;
var c = (String(message).length)-5;
var d = (String(message).length)-2;
var t0 = message.substring(b, a); //(-3,-3)
var t1 = message.substring(c, b); //(-5,-3)
var t2 = message.substring(d, tn); //(-2,0)
var na =  function(t0){return (t0*2)-1};
var nb =  function(t1){return (t1*2)-1};
var nc =  function(t2){return (t2*2)-1};
var T1 = xparray.find(function(element) {
    return element > t2});
var T2 = xparray.find(function(element) {
    return element > t0;
});
var T3 = xparray.find(function(element) {
    return element > t1;
});
var t3 = function(T1, T2, T3) {
    if (message.length = 7) {
        return T1 - T2;
    } else {
        return T1 - T3;
    }
};`

我希望这会从字符串 '!xp 40 60' 的末尾提取值 40 和 60，解释数组并提取 40 (3608200) 之后的下一个值和 60 (29470800) 之后的值，然后执行计算以将 40 值从60 值 (29470800-3608200)。到目前为止，我认为问题出在 T1、T2 和 T3 值上，因为它们总是返回 1，或者之后数组中的值1 (300)。

Answer 1

一维数组:

你可以用 indexOf 获取数组中 lvl 的索引，然后取下一个值(这是所需的 xp对于那个 lvl)。之后减去这两个，你就可以开始了:

var xparray = [1, 0, 2, 300, 3, 900, 4, 2000, 5, 3700, 6, 6000, 7, 10200, 8, 16200, 9, 23550, 10, 33480, 11, 45280, 12, 60880, 13, 80480, 14, 104180, 15, 130580, 16, 161080, 17, 196480, 18, 236980, 19, 282680, 20, 333680, 21, 390280, 22, 454180, 23, 525580, 24, 604680, 25, 691780, 26, 786980, 27, 896780, 28, 1021580, 29, 1161780, 30, 1317680, 31, 1480180, 32, 1656080, 33, 1845680, 34, 2049180, 35, 2267080, 36, 2499400, 37, 2749300, 38, 3017100, 39, 3303300, 40, 3608200, 41, 3932200, 42, 4272400, 43, 4629200, 44, 5002900, 45, 5393700, 46, 5801900, 47, 6239500, 48, 6707000, 49, 7205000, 50, 7734000, 51, 8598000, 52, 9656400, 53, 10923600, 54, 12478800, 55, 14350800, 56, 16568400, 57, 19160400, 58, 22155600, 59, 25582800, 60, 29470800, 61, 33940800, 62, 38813800, 63, 44129800, 64, 49938800, 65, 56302800, 66, 63297800, 67, 71019800, 68, 79594800, 69, 89187800, 70, 100013800, 71, 112462800, 72, 126343800, 73, 141899800, 74, 159398400, 75, 179148400, 76, 201478400, 77, 226818400, 78, 255468400, 79, 288218400, 80, 325868400];

var message = '!xp 40 60';

var lvls = [parseInt(message.split(' ')[1]), parseInt(message.split(' ')[2])]; // Getting the lvls in question
lvls = lvls.map(l => xparray[xparray.indexOf(l)+1]); // Getting the xp values in question
console.log(lvls[1] - lvls[0]); // Substract xp values

用二维数组(用map简化):

将该二维数组映射到 Map 或首先使用 Map。然后通过 lvl 键获取正确的 xp 值。

var xparray = [[1, 0], [2, 300], [3, 900], [4, 2000], [5, 3700]];
var xpMap = new Map(xparray); // Map constructor takes the two dimensional array (key=lvl, value=xp)

var message = '!xp 2 3';

var lvls = [parseInt(message.split(' ')[1]), parseInt(message.split(' ')[2])]; // Getting the lvls in question

lvls = lvls.map(l => xpMap.get(l)); // Just map it by getting the value for the key

console.log(lvls[1] - lvls[0]); // Substract xp values