javascript - 在字符串中的每个字符串实例之后插入一个空格

Question

我试图用空格分隔字符串中的单词。

例如，我想将 "twothousandninehundredfiftyeight" 转换为 "2958"(这样我可以稍后将其转换为 2958，但我我已经想通了)

我已经设法使用数组字典让它工作:

var dictionary = ["one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen","twenty","thirty","fourty","forty","fifty","sixty","seventy","eighty","ninety","hundred","thousand"];

连同这两个功能:

function spaceinsert(x) {
  for (i = 0; i < dictionary.length; i++) {
    if (x.includes(dictionary[i])) {
      var pos = getIndicesOf(dictionary[i], x);
      for (g = 0; g < pos.length; g++) {
            if (pos[g] != -1 && pos[g] !=0) {
                x = [x.slice(0, pos[g]), " ", x.slice(pos[g])].join('');    
            }
      }
    }
  }
  return x
}

和

function getIndicesOf(searchStr, str, caseSensitive) {
    var searchStrLen = searchStr.length;
    if (searchStrLen == 0) {
        return [];
    }
    var startIndex = 0, index, indices = [];
    if (!caseSensitive) {
        str = str.toLowerCase();
        searchStr = searchStr.toLowerCase();
    }
    while ((index = str.indexOf(searchStr, startIndex)) > -1) {
        indices.push(index);
        startIndex = index + searchStrLen;
    }
    return indices;
}

(对不起，乱七八糟的代码，我是新手)

这适用于大多数数字。例如:

onethousandthreehundredsixtyfive转换为 1365，但无法处理其他数字，例如 seventhousandtwohundredtwentytwo 它转换为 7200twent ytwo。 sixthousandfourhundredeightyeight 转换为 sixthousandfourhundredeighteight 我认为这与重复自身的“单词”有关(TWOhundredtwentyTWO ) 但我想不出解决这个问题的方法。

有什么想法吗？

Answer 1

按长度对字典进行排序，因此首先处理最长的单词，以防止“十四”拆分为“四十”，例如。

通过 | 连接字典单词创建一个 RegExp，并用括号括起来。使用标志 gi(全局，不区分大小写)。参见 regex101有关 RegExp 的更多信息。

现在将 String.replace() 与 patten 一起使用，并用匹配 + 空格替换每个匹配。 trim 结果以删除字符串后的空格。

const str = "twothousandninehundredfiftyeight"

var dictionary = ["one","two","three","four","five","six","seven","eight","nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen","twenty","thirty","fourty","forty","fifty","sixty","seventy","eighty","ninety","hundred","thousand"].sort((a, b) => b.length - a.length)

const pattern = new RegExp(dictionary.join('|'), 'gi')

const result = str.replace(pattern, '$& ').trim()

console.log(result)