我有一个嵌套映射来遍历我的数据,然后为我的数据中的每个对象返回一个 react 组件。检查下面的代码:
return props.dataArray.map((classObj) => {
return classObj.timetable.map((timetableObj) => {
if (timetableObj.weekday === props.day) {
return ttCard({
lecturer: classObj.lecturer,
module: classObj.module,
room: classObj.room,
class_id: classObj.id,
timetable_id: timetableObj.id,
startTime: timetableObj.start_time,
endTime: timetableObj.end_time,
weekday: timetableObj.weekday
});
}
return null;
});
});
我的问题是我的组件没有排序,它们必须排序,因为这是学生的时间表。查看下图,注意 10:30 AM 是我的选项卡 View 中的最新卡片:
到目前为止我尝试过的事情:
1- 创建一个新数组,然后在 if 语句
block 之后对其进行排序 - 不起作用
2- 将排序数组返回给函数并映射该数组以返回组件 - 不起作用
3- 在组件参数中循环并将对象作为函数返回:
ttCard( sortedArr.forEach((ttObject) => {
return ttObject
}))
也没有工作
我用谷歌搜索并尝试进行研究,但到目前为止没有希望。我知道最初我的嵌套 map 很糟糕,但这是我的对象的样子:
[
{
"class_code": "English-5-G-2-L-1911-test-teacher",
"id": 23,
"lecturer": "test teacher",
"module": "English-5",
"room": "L",
"timetable": [
{
"end_time": "9:00",
"id": 37,
"start_time": "8:00",
"weekday": "Sunday"
},
{
"end_time": "10:00",
"id": 38,
"start_time": "9:00",
"weekday": "Sunday"
},
{
"end_time": "10:00",
"id": 47,
"start_time": "9:00",
"weekday": "Monday"
},
{
"end_time": "10:00",
"id": 48,
"start_time": "9:00",
"weekday": "Tuesday"
},
{
"end_time": "11:30",
"id": 52,
"start_time": "10:30",
"weekday": "Tuesday"
},
{
"end_time": "11:30",
"id": 54,
"start_time": "10:30",
"weekday": "Thursday"
},
{
"end_time": "12:30",
"id": 58,
"start_time": "11:30",
"weekday": "Thursday"
},
{
"end_time": "14:00",
"id": 61,
"start_time": "13:00",
"weekday": "Wednesday"
}
]
}
]
最佳答案
您可以在输出中使用 sort
来按 startTime 排列数组
.sort((a, b) => {
// These lines are so we can directly compare the times
// I would recommend to send timestamps down with your data (if possible)
var aTime = a.startTime.replace(':', '');
var bTime = b.startTime.replace(':', '');
// Sort by smallest first
return aTime - bTime;
});
我还建议过滤掉数组中的空值
用你的例子 -
var classesArr = props.dataArray.map((classObj) => {
return classObj.timetable.map((timetableObj) => {
if (timetableObj.weekday === props.day) {
return {
lecturer: classObj.lecturer,
module: classObj.module,
room: classObj.room,
class_id: classObj.id,
timetable_id: timetableObj.id,
startTime: timetableObj.start_time,
endTime: timetableObj.end_time,
weekday: timetableObj.weekday
}
}
return null;
}).filter(x => x); // Filter out any null values
}).filter(x => x); // Filter out any null values.
// Flatten array so it is sortable/mapable
return [].concat.apply([], classesArr).sort((a, b) => {
// These lines are so we can directly compare the times
// I would recommend to send timestamps down with your data (if possible)
var aTime = a.startTime.replace(':', '');
var bTime = b.startTime.replace(':', '');
// Sort by smallest time first
return aTime - bTime;
}).map((x) => {
return ttCard(x);
})
关于javascript - 如何在 React Native 中对组件数组进行排序?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/59428784/