when(candidateService.findById(1)).thenReturn(new Candidate());
我想将此行为扩展到任何整数(不一定是 1)
如果我写
when(candidateService.findById( any(Integer.class) )).thenReturn(new Candidate());
我有编译错误
The method findById(Integer) in the type CandidateService is not applicable for the arguments (Matcher)
更新
导入:
import static org.junit.Assert.assertEquals;
import static org.mockito.Matchers.anyInt;
import static org.mockito.Matchers.anyString;
import static org.mockito.Mockito.mock;
import static org.mockito.Mockito.times;
import static org.mockito.Mockito.verify;
import static org.mockito.Mockito.when;
import static org.springframework.test.web.servlet.result.MockMvcResultMatchers.status;
import java.util.ArrayList;
import java.util.HashSet;
import org.junit.Before;
import org.junit.Test;
import org.junit.runner.RunWith;
import org.mockito.InjectMocks;
import org.mockito.Mock;
import org.mockito.MockitoAnnotations;
最佳答案
试试 anyInt():
when(candidateService.findById(anyInt())).thenReturn(new Candidate());
例如,我的项目中有 anyLong():
when(dao.getAddress(anyLong())).thenReturn(Arrays.asList(dto));
编辑: 您必须导入:
import static org.mockito.Matchers.anyInt;
关于java - 为任何整数输入参数设置模拟返回值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19155369/