我在使这部分代码工作时遇到问题,基本上我想调用这个将变量发送到 PHP 页面的函数。我测试了该变量是否存在,并且还测试了我的 php 页面是否按应有的方式接受信息,但是我无法使这个 Ajax 工作正常。
function ajaxRequest(myname) {
var AJAX = null; // Initialize the AJAX variable.
if (window.XMLHttpRequest)
{ // Does this browser have an XMLHttpRequest object?
AJAX=new XMLHttpRequest(); // Yes -- initialize it.
} else
{ // No, try to initialize it IE style
AJAX=new ActiveXObject("Microsoft.XMLHTTP"); // Wheee, ActiveX, how do we format c: again?
} // End setup Ajax.
if (AJAX==null)
{ // If we couldn't initialize Ajax...
alert("Your browser doesn't support AJAX."); // Sorry msg.
return false // Return false, couldn't set up ajax
}
AJAX.onreadystatechange = function()
{ // When the browser has the request info..
if (AJAX.readyState==4 || AJAX.readyState=="complete")
{ // see if the complete flag is set.
callback(AJAX.responseText, AJAX.status); // Pass the response to our processing function
} // End Ajax readystate check.
}
alert("Alert1");
var url='http://localhost/main.php?Name=myname';
AJAX.open("POST", url, true); // Open the url this object was set-up with.
alert("Alert2");
AJAX.send(); // Send the request.
这是我的 php 部分,它应该接受变量
<?php
$var=$_GET['Name'];
echo $var;
?>
最佳答案
好的,首先您需要将您的请求从 POST 更改为 GET 喜欢
AJAX.open("GET", url, true); // Open the url this object was set-up with.
你还需要更新这一行 来自
var url='http://localhost/main.php?Name=myname';
到
var url='http://localhost/main.php?Name='+myname;
我的完整脚本是:
<script type="text/javascript">
function ajaxRequest(myname) {
var AJAX = null; // Initialize the AJAX variable.
if (window.XMLHttpRequest)
{ // Does this browser have an XMLHttpRequest object?
AJAX=new XMLHttpRequest(); // Yes -- initialize it.
} else { // No, try to initialize it IE style
AJAX=new ActiveXObject("Microsoft.XMLHTTP"); // Wheee, ActiveX, how do we format c: again?
} // End setup Ajax.
if (AJAX==null)
{ // If we couldn't initialize Ajax...
alert("Your browser doesn't support AJAX."); // Sorry msg.
return false // Return false, couldn't set up ajax
}
AJAX.onreadystatechange = function()
{ // When the browser has the request info..
if (AJAX.readyState==4 || AJAX.readyState=="complete")
{ // see if the complete flag is set.
callback(AJAX.responseText, AJAX.status); // Pass the response to our processing function
} // End Ajax readystate check.
}
alert("Alert1");
var url='http://localhost/main.php?Name='+myname;
AJAX.open("GET", url, true); // Open the url this object was set-up with.
alert("Alert2");
AJAX.send(); // Send the request.
}
</script>
你可能还缺少回调函数,所以添加它,使其看起来像这样
function callback(x, y) {
alert(x);
}
然后调用你的 AJAX 函数
ajaxRequest("ashley");
这是您需要的 main.php 代码(尽管这不是您应该使用 AJAX 的目的
<?php
session_start();
if(isset($_GET["Name"])) {
$_SESSION["Name"] = $_GET["Name"];
}
if(isset($_SESSION["Name"])) {
echo $_SESSION["Name"];
} else {
echo "The AJAX has not been run!";
}
?>
关于php - Javascript-Ajax 无法发送任何数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11810236/