javascript - 如何修复 jQuery 1.8 “unsupported pseudo: all” 错误？

Question

它适用于 jquery 1.3，但是当我尝试用 1.8 替换它时，我得到“不支持的伪:全部”错误:

这是我当前的代码:

 $(function () {
            $('input[id$=btnAdd]').click(function (e) {
                e.preventDefault();
                // Assuming you get a JSON object from a service
                var lenBefore = $('select[id$=DDL] :all').length;
                var obj = { "6": "Item6", "7": "Item7", "8": "Item8" };
                $.each(obj, function (value, text) {
                    $('select[id$=DDL]').append($('<option></option>').val(value).html(text))
                });
                var lenAfter = $('select[id$=DDL] :all').length;
                $("#para").html("<b>" + (lenAfter - lenBefore) + "</b>" + " new items were added");
                $(this).attr("disabled", "disabled");
            });
        });

您的回答会很有帮助。

Answer 1

我想你想要 $('select[id$=DDL] option') 或 $('select[id$=DDL] *') 或 $('select[id$=DDL]').children()