javascript - 在 PHP Echo 中调用 Javascript 函数

Question

引用This link ，我正在尝试从表中动态删除行。这是我的 Javascript 函数:

function deleteBox(id){

alert ("Inside Method");
if (confirm("Are you sure you want to delete this record?"))
{
  var dataString = 'id='+ id;
  $("#flash_"+id).show();
  $("#flash_"+id).fadeIn(400).html('<img src="img/loading.gif" /> ');
  $.ajax({
  type: "POST",
  url: "delete.php",
  data: dataString,
  cache: false,
  success: function(result){
           if(result){
                $("#flash_"+id).hide();
                // if data delete successfully
                if(result=='success'){
                     //Check random no, for animated type of effect
                     var randNum=Math.floor((Math.random()*100)+1);
                     if(randNum % 2==0){
                        // Delete with slide up effect
                        $("#list_"+id).slideUp(1000);
                     }else{
                        // Just hide data
                        $("#list_"+id).hide(500);
                     }

                }else{
                     var errorMessage=result.substring(position+2);
                     alert(errorMessage);
                }
          }
  }
  });
}
}

但是，在 Php 中从 Echo 调用它似乎并没有调用它。这是我的 PHP 代码:

echo "<td align=\"center\">" . $id."</td>";
echo "<td><a href = 'javascript:deleteBox($id)'>Delete</a></td>";

不对的地方请指正。非常感谢尽早提供帮助。

Answer 1

<td><a href = 'javascript:deleteBox($id)'>Delete</a></td>

到

echo "<td><a onClick='deleteBox(" . $id . ");'>Delete</a></td>"; 

在我看来，这就是我会做的......

编辑并缩短了jscript；

function deleteBox(idDelete){

alert ("Inside Method");
if (confirm("Are you sure you want to delete this record?"))
{
  $("#flash_" + idDelete).show();
  $("#flash_" + idDelete).fadeIn(400).html('<img src="img/loading.gif" /> ');

  $.post('delete.php', {'id': idDelete}, function(result) {
            if(result){
                $("#flash_" + idDelete).hide();
                // if data delete successfully
                if(result=='success'){
                     //Check random no, for animated type of effect
                     var randNum=Math.floor((Math.random()*100)+1);
                     if(randNum % 2==0){
                        // Delete with slide up effect
                        $("#list_" + idDelete).slideUp(1000);
                     }else{
                        // Just hide data
                        $("#list_" + idDelete).hide(500);
                     }

                }else{
                     var errorMessage=result.substring(position+2);
                     alert(errorMessage);
                }
          }
  });  
} 

在你的 delete.php 中:

$_POST['id'] 

检索 ID。