javascript - 按钮发布错误

Question

<div class="buttons"> <a href="#" class="btn btnGreen"><span>Beta Signup</span></a> <span><em>or</em></span>
      <a onclick="test()" class="btn btnBlue"><span>Donate to Development</span></a> </div>

      <form action="https://www.paypal.com/cgi-bin/webscr" method="post" target="_top">
      <input type="hidden" name="cmd" value="_s-xclick">
      <input type="hidden" name="hosted_button_id" value="JZDSU6T647PL4">
      <input type="image" src="https://www.paypalobjects.com/en_US/i/btn/btn_donate_SM.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!">
      <img alt="" border="0" src="https://www.paypalobjects.com/en_US/i/scr/pixel.gif" width="1" height="1">
      </form>


  </div>

我希望在单击捐赠给开发按钮时发生表单中的操作，我该怎么做？？？我想要来自 btn btnblue 类的图像，但它不会转移到表单

Answer 1

您需要创建一个通过 javascript 提交表单的函数。例如。

<a onclick="submit()" class="btn btnBlue"><span>Donate to Development</span></a>

function submit() {
  var form = document.querySelector('form');
  if(whatever){
   form.submit();
  }
}