我正在构建一个 node express angular twitter 状态分析器,我正在尝试弄清楚如何从中提取 tex 并将其分配给一个长字符串以备后用。
我正在尝试像这样拉取用户状态:
client.get('statuses/user_timeline', {params, count:20}, function(error, tweets, response) {
var jsonObject;
if (!error) {
analyze.analyze(tweets);
}
});
响应看起来像这样:
[
{
"coordinates": null,
"favorited": false,
"truncated": false,
"created_at": "Wed Aug 29 17:12:58 +0000 2012",
"id_str": "240859602684612608",
"entities": {
"urls": [
{
"expanded_url": "/blog/twitter-certified-products",
"url": "",
"indices": [
52,
73
],
"display_url": "
}
],
"hashtags": [
],
"user_mentions": [
]
},
"in_reply_to_user_id_str": null,
"contributors": null,
"text": "Introducing the Twitter Certified Products Program: ",
"retweet_count": 121,
"in_reply_to_status_id_str": null,
"id": 240859602684612608,
"geo": null,
"retweeted": false,
"possibly_sensitive": false,
"in_reply_to_user_id": null,
"place": null,
"user": {
"profile_sidebar_fill_color": "DDEEF6",
"profile_sidebar_border_color": "C0DEED",
"profile_background_tile": false,
"name": "Twitter API",
"profile_image_url": ",
"created_at": "Wed May 23 06:01:13 +0000 2007",
"location": "San Francisco, CA",
"follow_request_sent": false,
"profile_link_color": "0084B4",
"is_translator": false,
"id_str": "6253282",
"entities": {
"url": {
"urls": [
{
"expanded_url": null,
"url": "",
"indices": [
0,
22
]
}
]
},
"description": {
"urls": [
]
}
},
我现在的代码是这样的:
function analyze(data) {
for (var i = 0; i < data.length; i++) {
tweet = data[i]['text'];
tweet = tweet.replace('#' , '');
return console.log(tweet);
}
}
module.exports.analyze = analyze;
目前,我在分析函数的输出中只得到一条推文。我究竟做错了什么?
谢谢。
最佳答案
要拉出一个包含所有推文文本但不带#
的数组,您可以这样做:
function analyze(data) {
return data.map(function(item) {
return item.text.replace('#' , '');
});
}
module.exports.analyze = analyze;
关于javascript - 遍历对象数组以提取特定数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41078400/