python - 如何按列和索引连接 Pandas DataFrames？

Question

我有四个带有数字列和索引的 Pandas DataFrame:

A = pd.DataFrame(data={"435000": [9.792, 9.795], "435002": [9.825, 9.812]}, index=[119000, 119002])
B = pd.DataFrame(data={"435004": [9.805, 9.783], "435006": [9.785, 9.78]}, index=[119000, 119002])
C = pd.DataFrame(data={"435000": [9.778, 9.743], "435002": [9.75, 9.743]}, index=[119004, 119006])
D = pd.DataFrame(data={"435004": [9.743, 9.743], "435006": [9.762, 9.738]}, index=[119004, 119006])

我想像这样将它们连接成一个 DataFrame，匹配列名和索引:

如果我尝试 pd.concat 四个 df，它们会堆叠(根据 axis 的不同，它们会堆叠在一起(在上方和下方，或在侧面)，我最终会在 df 中具有 NaN 值:

result = pd.concat([A, B, C, D], axis=0)

如何使用 pd.concat(或 merge、join 等)获得正确的结果？

Answer 1

你需要成对连接:

result = pd.concat([pd.concat([A, C], axis=0), pd.concat([B, D], axis=0)], axis=1)
print (result)
        435000  435002  435004  435006
119000   9.792   9.825   9.805   9.785
119002   9.795   9.812   9.783   9.780
119004   9.778   9.750   9.743   9.762
119006   9.743   9.743   9.743   9.738

更好的是stack + concat + unstack :

result = pd.concat([A.stack(), B.stack(), C.stack(), D.stack()], axis=0).unstack()
print (result)
        435000  435002  435004  435006
119000   9.792   9.825   9.805   9.785
119002   9.795   9.812   9.783   9.780
119004   9.778   9.750   9.743   9.762
119006   9.743   9.743   9.743   9.738

更动态:

dfs = [A,B,C,D]
result = pd.concat([df.stack() for df in dfs], axis=0).unstack()
print (result)
        435000  435002  435004  435006
119000   9.792   9.825   9.805   9.785
119002   9.795   9.812   9.783   9.780
119004   9.778   9.750   9.743   9.762
119006   9.743   9.743   9.743   9.738