javascript - 将数组中对象的最大值显示为两个最大值

Question

我有一个来自 api 响应及其对象的数组。我需要找到具有最大总计的值并且我已经显示它我无法解决它，当总计有两个最大值时。是否有有什么解决办法吗？

myArray[
{time: "2018-12-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-13-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-14-02", total: 35, percentage: 25, averageTime: 25},
{time: "2018-16-02", total: 65, percentage: 60, averageTime: 20},
{time: "2018-17-02", total: 40, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 65, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 35, percentage: 23, averageTime: 20}
];

我试过这样的 reduce 函数:

var data =[];
data.reduce((max, p) => p.total > max ? p.total : max, data[0].total);

Answer 1

你可以这样做:

想法:

• 创建一个以 total 作为键和一个变量来保存最大值的 hashMap。
• 检查键是否存在，如果不存在，将其初始化为一个数组。
• 将当前对象压入该数组。
• 获取以 max 为键的数组，您将获得总计最大的所有值。

现在您已经有了整个对象，您可以迭代并显示任何必要的值。

var myArray = [{time: "2018-12-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-13-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-14-02", total: 35, percentage: 25, averageTime: 25},
{time: "2018-16-02", total: 65, percentage: 60, averageTime: 20},
{time: "2018-17-02", total: 40, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 65, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 35, percentage: 23, averageTime: 20}]

var max = 0;
var hashMap = myArray.reduce((acc, p) => {
  max = Math.max(max, p.total);
  acc[p.total] = acc[p.total] || [];
  acc[p.total].push(p);
  return acc;
}, {});

console.log(hashMap[max]);

只有时间值(value)

var myArray = [{time: "2018-12-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-13-02", total: 25, percentage: 20, averageTime: 20},
{time: "2018-14-02", total: 35, percentage: 25, averageTime: 25},
{time: "2018-16-02", total: 65, percentage: 60, averageTime: 20},
{time: "2018-17-02", total: 40, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 65, percentage: 20, averageTime: 20},
{time: "2018-18-02", total: 35, percentage: 23, averageTime: 20}]

var max = 0;
var hashMap = myArray.reduce((acc, p) => {
  max = Math.max(max, p.total);
  acc[p.total] = acc[p.total] || [];
  acc[p.total].push(p.time);
  return acc;
}, {});

console.log(hashMap[max]);