javascript - jQuery 选择器除父级为 div 之外的所有元素

Question

以下是我的 HTML:

<div id="formdata">    
  <div id="to_select">
    <input type='hidden' name='to_be_selected' value='a' />
    <input type='hidden' name='also_to_be_selected' value='a' />
  </div>
  <input type='hidden' name='to_be_selected_too' value='a' />
  <div id="not_to_select">
    <input type='hidden' name='not_to_select' value='not selected'/>
  </div>    
</div>

如何仅选择不在 div#not_to_select 中的元素

以下是我尝试过的:

$("#formdata div:not(#not_to_select)").find('input')

$("#formdata").not("div#not_to_select").find('input,select,textarea')

$("#formdata").find('input,select,textarea').filter(function(){
      return $(this).parent().is(":not(#not_to_select)");
})

Answer 1

要实现此目的，您可以使用 filter() 排除作为 #not_to_select 后代的 inputs:

var $inputs = $('#formdata input').filter(function() {
  return $(this).closest('#not_to_select').length == 0;
});

$inputs.addClass('foo');

.foo { border: 1px solid #C00; }

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="formdata">
  <div id="to_select">
    <input type="text" name="to_be_selected" value="a" />
    <input type="text" name="also_to_be_selected" value="a" />
  </div>
  <input type="text" name="to_be_selected_too" value="a" />
  <div id="not_to_select">
    <input type="text" name="not_to_select" value="not selected" />
  </div>
</div>

或者，您可以使用 :not() 来排除它们:

var $inputs = $('#formdata input:not(#not_to_select input)');

$inputs.addClass('foo');

.foo { border: 1px solid #C00; }

<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="formdata">
  <div id="to_select">
    <input type="text" name="to_be_selected" value="a" />
    <input type="text" name="also_to_be_selected" value="a" />
  </div>
  <input type="text" name="to_be_selected_too" value="a" />
  <div id="not_to_select">
    <input type="text" name="not_to_select" value="not selected" />
  </div>
</div>