javascript - 在使用 substr 制作句子计数器时遇到问题

Question

我正在尝试反句，我几乎已经完成了。我做了一个但是我有一个问题，每当有多个句点、问号或感叹号时，它们似乎也被计算在内

html

 <input id="counter" type="text" />
<p id="sntnceCounter">Sentence(s):</p>

js

function myFunction() {
  var counter = document.getElementById("counter").value;
  var sentences = document.getElementById("sntnceCounter");

 for (var i = 0; i < counter.length; i++) {
    var currentCharacter = counter.substr(i, 1);
    var nextCharacter = counter.substr(i + 1, 1);
 if (
      (currentCharacter == "." ||
        currentCharacter == "?" ||
        currentCharacter == "!") &&
      (nextCharacter !== "." || nextCharacter !== "?" || nextCharacter !== "!")
    ) {
      console.log((sntnceCount += 1));
    }
  }

  sentences.innerHTML = "Sentence(s):" + sntnceCount;
}

我通过检查当前字符是句号、问号还是感叹号来计算句子，并确保如果有下一个字符则不计算在内。但它仍然算他们。我该如何解决这个问题？

抱歉英语不好

Answer 1

你应该改变

(nextCharacter !== "." || nextCharacter !== "?" || nextCharacter !== "!")

到

(nextCharacter !== "." && nextCharacter !== "?" && nextCharacter !== "!")