我在使用以下代码片段时遇到问题:
<!DOCTYPE html>
<html>
<head>
<title>Hangman</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<script type="text/javascript">
<!--
gallows = new Array("--------\n| |\n|\n|\n|\n|\n=====",
"--------\n| O\n|\n|\n|\n|\n=====",
"--------\n| O\n| |\n|\n|\n|\n=====",
"--------\n| O\n| \\|\n|\n|\n|\n=====",
"--------\n| O\n| \\|/\n|\n|\n|\n=====",
"--------\n| O\n| \\|/\n| |\n|\n|\n=====",
"--------\n| O\n| \\|/\n| |\n| /\n|\n=====",
"--------\n| O\n| \\|/\n| |\n| / \\\n|\n=====");
guessChoices = new Array("JavaScript", "Navigator", "LiveConnect", "LiveWire");
guessed = [];
function startAgain()
{
guesses = 0;
max = gallows.length - 1;
//guessed = " ";
len = guessChoices.length - 1;
toGuess = guessChoices[Math.round(len*Math.random())].toUpperCase();
displayHangman();
displayToGuess();
displayGuessed();
}
function stayAway()
{
document.game.elements[3].focus();
alert("Don't mess with this form element!");
}
function displayHangman()
{
document.game.status.value=gallows[guesses];
}
function displayToGuess()
{
pattern = "";
for(i=0;i<toGuess.length;++i)
{
if(guessed.indexOf(toGuess.charAt(i)) != -1)
pattern += (toGuess.charAt(i)+" ");
else pattern += "_ ";
}
document.game.toGuess.value=pattern;
}
function displayGuessed(s)
{
result="";
for(i in s)
{
guess=s[i];
result += guess;
}
document.game.guessed.value=result;
//document.game.guessed.value=guessed;
}
function badGuess(s)
{
if(toGuess.indexOf(s) == -1) return true;
return false;
}
function winner()
{
for(i=0;i<toGuess.length;++i)
{
if(guessed.indexOf(toGuess.charAt(i)) == -1) return false;
}
return true;
}
function guess(s)
{
if(guessed.indexOf(s) == -1) guessed.push(s);
if(badGuess(s)) ++guesses;
displayHangman();
displayToGuess();
displayGuessed(guessed);
if(guesses >= max)
{
alert("You're dead. The word you missed was "+toGuess+".");
startAgain();
}
if(winner())
{
alert("You won!");
startAgain();
}
}
// -->
</script>
</head>
<body>
<h1>Hangman</h1>
<form name="game">
<pre>
<textarea name="status" rows="7" cols="16" onfocus="stayAway();"></textarea>
</pre>
<p>
<input type="text" name="toGuess" onfocus="stayAway();"> Word to guess<br>
<input type="text" name="guessed" onfocus="stayAway();"> Letters guessed so far<br>
</p>
<p>Enter your next guess.</p>
<p>
<input type="text" name="input" size=1 value="">
<input type = "button" value = "guess" onclick = "guess(game.input.value); game.input.value = '';">
</p>
<input type="button" name="restart" value="---- Start Again ----" onclick="startAgain();">
<script type="text/javascript">
<!--
startAgain();
// -->
</script>
</form>
</body>
</html>
在我单击 game.guess 按钮后，第一次，我得到了预期的输出... game.input 清除并显示 guessed。但是，我第二次单击具有不同值的猜测按钮时，收到错误消息:
guess is not a function
| onclick()
| event = click clientX=77, clientY=33
guess(game.input.value) onclick(line 2)
老实说，我不明白为什么。我做错了什么？
(我从 James Jaworski 的 Mastering JavaScript, Premium Edition 中获得了大部分代码)
最佳答案
问题出在这几行:
guess=s[i];
result += guess;
这样你就改变了guess的上下文。如果将此行更改为
result += s[i];
您的错误将会消失。
您将函数与对变量使用相同的名称相冲突。
请记住使用 var 关键字定义变量并避免此类混淆。
1 - 尽可能使用匿名函数
2 - 声明和使用局部变量
为了避免冲突。
关于Javascript 函数停止被识别，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/9857929/