javascript - 在JavaScript中将相似的对象组合在一起

Question

我有一些正在获取JSON的JavaScript，并且我试图将某些信息行组合在一起以在表中使用。

JSON如下所示：

[{"Code":"12345","Name":"foo","Service":"Payments"},
{"Code":"12345","Name":"foo","Service":"Marketing"},
{"Code":"23456","Name":"bar","Service":"Payments"},
{"Code":"23456","Name":"bar","Service":"Development"},
{"Code":"34567","Name":"baz","Service":"Marketing"}]

基本上，有些行彼此共享完全相同的信息，除了一个字段Service。

我的想法是尝试将每一行变成一个对象，我可以更新该对象或与共享同一Code的另一个对象合并。

该对象和代码如下所示：

function CustObj(code,name,hasPay,hasMarket,hasDev) {
  this.code = code;
  this.name = name;
  this.hasPay = hasPay;
  this.hasMarket = hasMarket;
  this.hasDev = hasDev;
}

function formatData(data) {
  var formatedData = [];
  for (var key in data) {
    var customer = new CustObj(data[key].Code,data[key].Name);
    switch (data[key].Service) {
      case 'Payments':
        customer.hasPay = true;
        break;
      case 'Marketing':
        customer.hasMarket = true;
        break;
      case 'Development':
        customer.hasDev = true;
        break;
    }
    formatedData.push(school);
  }
}

问题是我想为每个唯一的Code创建一个对象，但是该对象具有基于Service的正确标记数量，但是我还没有弄清楚该怎么做。我当时正在考虑做类似$.extend(formatedData,customer)的操作来合并对象，但是似乎找不到正确的逻辑来定位我要合并的两个对象。

关于如何实现这一目标有什么想法？

Answer 1

您可以处理重复数组，并创建一个新数组，其中“ Service”属性是共享相同Code和Name的服务数组：

var data = [
    {"Code":"12345","Name":"foo","Service":"Payments"},
    {"Code":"12345","Name":"foo","Service":"Marketing"},
    {"Code":"23456","Name":"bar","Service":"Payments"},
    {"Code":"23456","Name":"bar","Service":"Development"},
    {"Code":"34567","Name":"baz","Service":"Marketing"}
];

function mergeServices(data) {
    var result = [], item, match, found;
    // for each array item
    for (var i = 0; i < data.length; i++) {
        item = data[i];
        found = false;
        for (var j = 0; j < result.length; j++) {
            // see if we have a dup of a previously existing item
            if (item.Code == result[j].Code && item.Name == result[j].Name) {
                // just add the Service name to the array of the previous item
                result[j].Service.push(item.Service);
                found = true;
                break;
            }
        }
        if (!found) {
            // copy the current row (so we can change it without changing original)
            var newItem = {};
            for (var prop in item) {
                newItem[prop] = item[prop];
            }
            // convert service to an array
            newItem.Service = [newItem.Service];
            result.push(newItem);
        }
    }
    return result;
}

var output = mergeServices(data);

产生这个output：

[
    {"Code":"12345","Name":"foo","Service":["Payments","Marketing"]},
    {"Code":"23456","Name":"bar","Service":["Payments","Development"]},
    {"Code":"34567","Name":"baz","Service":["Marketing"]}
]

工作jsFiddle：http://jsfiddle.net/jfriend00/6rU2z/