javascript - 为什么这种情况不能正常工作？

Question

我必须制作一个数字猜谜游戏，您可以尝试 3 次来猜测 1 到 5 之间的数字。每次猜错之后，它都会显示您还剩下多少次尝试。当您猜对时，您会收到一条祝贺信息。当您的猜测用完时，您会收到一条消息。但是，当您用完所有猜测时，我无法收到消息。为什么不运行？

<script type="text/javascript">
    var tries=3;
    alert("Guess the number I'm thinking of between 1 and 5. You've got 3  tries.");
    var attempt =  prompt(tries+" tries remaining. Enter your guess.");
    var randomnumber = Math.random() * 5; 
    randomnumber = Math.ceil(randomnumber);
    while (tries>=2){
        if(attempt!=randomnumber){
            tries--;
            prompt("Wrong! You have " + tries + " left ");
        }
        else if(tries<1){
            alert("You have no tries left");
        }
        else {
            alert("Congratulations! You guessed the correct number");
            return;
        }
    }
</script>

Answer 1

只有在尝试次数超过 2 次或恰好 2 次时，您才会进入循环。否则你的 if 语句不会被执行。您可能必须将 if 与 while 分开。

<script type="text/javascript">
    var tries=3;
    alert("Guess the number I'm thinking of between 1 and 5. You've got 3  tries.");
    var attempt =  prompt(tries+" tries remaining. Enter your guess.");
    var randomnumber = Math.random() * 5; 
    randomnumber = Math.ceil(randomnumber);
    while (tries-1 > 0){
        if(attempt!=randomnumber){
            tries--;
            prompt("Wrong! You have " + tries + " left ");
        }
        else {
            alert("Congratulations! You guessed the correct number");
            return;
        }
    }
    alert("You have no tries left");
</script>