javascript - 比较值，如果匹配则添加到数组

Question

我试图将 2 个数据源合并为 1 个数据源，我想遍历它们，如果特定值匹配，则将其添加到具有相同值的第一个对象，然后将已存在的空数组添加到空数组中。不管我有多少对象。

假设我有这些信息

来源 1

one = {
    "teams": [
        {
            name: 'ABC',
            members: [],
            rooms: '0'
        },
        {
            name: 'DEF',
            members: [],
            rooms: '1'
        }
    ]
}

来源 2

two = {
    "persons": [
        {
            name: 'Foo',
            gender: 'male',
            room: '1'
        },
        {
            name: 'Bar',
            gender: 'female',
            room: '2'
        }
    ]
}

我想要的是，如果“room and rooms”值匹配，则“persons”数组合并到 members 数组。

我假设是这样的:

 for(var i = 0 ; i < two.persons.length; i++) {
    if (one.teams[i].rooms == two.persons[i].room) {
            data.teams[i].members.push(two.persons[i]);
        }
 }

Answer 1

使用高阶方法你可以:

one = {
    "teams": [
        {
            name: 'ABC',
            members: [],
            rooms: '0'
        },
        {
            name: 'DEF',
            members: [],
            rooms: '1'
        }
    ]
};

two = {
    "persons": [
        {
            name: 'Foo',
            gender: 'male',
            room: '1'
        },
        {
            name: 'Bar',
            gender: 'female',
            room: '2'
        }
    ]
};

var ttt = one.teams.map(function(x){
var roomVal= x.rooms;
    
   x.members = two.persons.filter(function(t){
      return t.room == roomVal});
   return x;
})

one.teams = ttt;
console.log(one)