我是 node.js 的新手。我正在尝试创建一个注册页面并使用 mysql 将输入的值保存在数据库中。
我可以通过在请求 header 上传递参数来做到这一点。但是,在请求 header 中传递参数始终不是一个好主意。所以尝试在请求体上传递参数。
我正在使用 Postman 来测试我的 node.js 服务。
这是我的演示应用程序的 github 链接
https://github.com/debasish283/node_gulp
我还需要做什么才能在请求正文中传递参数?
在请求正文中传递参数时出现以下错误。
TypeError: Cannot read property 'firstname' of undefined
at Object.db.register (/var/projects/node_gulp/server/db.js:13:65)
at wrapper.register (/var/projects/node_gulp/server/wrapper.js:8:12)
at Layer.handle [as handle_request] (/var/projects/node_gulp/node_modules/express/lib/router/layer.js:95:5)
at next (/var/projects/node_gulp/node_modules/express/lib/router/route.js:131:13)
at Route.dispatch (/var/projects/node_gulp/node_modules/express/lib/router/route.js:112:3)
at Layer.handle [as handle_request] (/var/projects/node_gulp/node_modules/express/lib/router/layer.js:95:5)
at /var/projects/node_gulp/node_modules/express/lib/router/index.js:277:22
at Function.process_params (/var/projects/node_gulp/node_modules/express/lib/router/index.js:330:12)
at next (/var/projects/node_gulp/node_modules/express/lib/router/index.js:271:10)
at Function.handle (/var/projects/node_gulp/node_modules/express/lib/router/index.js:176:3)
代码: 服务器 -> wrapper.js
var express = require('express');
var db = require('./db.js');
var config = require('config');
var wrapper = {
register: function(req, res) {
console.log('inside wrapper');
db.register(req.body);
}
};
module.exports = wrapper;
路由 -> index.js
var router = require('express').Router();
var wrapper = require('../server/wrapper');
router.post('/register', wrapper.register);
module.exports = router;
app.js
var express = require('express');
var app = express();
var port = process.env.PORT || 3000;
var router = require('./routes');
var bodyParser = require('body-parser');
app.use('/', router);
app.use(bodyParser.urlencoded({ extended: false }));
app.use(bodyParser.json());
app.listen(port, function() {
console.log('Server started at ' + port);
});
服务器-> db.js
var mysql = require('mysql');
var config = require('config');
var connection = mysql.createConnection({
host: config.get('database.host'),
user: config.get('database.user'),
password: config.get('database.password'),
database: config.get('database.database')
});
var db = {
register: function(parameter) {
var qry = 'insert into users values (' + "'" + parameter.firstname + "'" + ',' + "'" + parameter.lastname + "'" + ',' + "'" + parameter.username + "'" + ',' + "'" + parameter.bday + "'" + ',' + "'" + parameter.gender + "'" + ',' + "'" + parameter.password + "'" + ')';
console.log(qry);
connection.connect();
connection.query(qry, function(err, rows, fields) {
if (!err) {
console.log('The solution is: ', rows);
} else
console.log('Error while performing Query.' + err);
});
connection.end();
}
};
module.exports = db;
最佳答案
您需要在路由之前移动您的主体解析中间件,以便在执行您的路由处理程序之前首先解析请求主体:
// app.js
// ...
app.use(bodyParser.urlencoded({ extended: false }));
app.use(bodyParser.json());
app.use('/', router);
// ...
关于javascript - Node.js 无法读取未定义的属性“名字”,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/39409982/