Javascript:拼接多维对象

Question

我有这个 Object/Array 结构:

Obj = {
    "User": {
        "user1": [{
            "desc": "NG60",
            "Id": 3473631702,
            "Status": "offline"
        }],

        "user2": [{
            "desc": "somevalue",
            "Id": 963346121,
            "Status": "offline"
        },
        {
            "desc": "othervalue",  // SPLICE THIS OUT
            "Id": 963346122,      // SPLICE THIS OUT
            "Status": "offline"  // SPLICE THIS OUT
        }],

        "user3": [{
            "desc": "whatever",
            "Id": 972878784
        }]
    }
}

我想动态地过滤掉不同的值(在这个例子中固定) 如果没有 ID，我想删除整个用户数组。

例如，如果我想过滤掉 user2 的第二个数组元素:

 for(var users in Obj) {
     for(var Ids in Obj[users]) {
         if(Obj[users][Ids].Id == 963346122){
             Obj[users][Ids].splice(0, 1); // ERROR HERE
         }
     }
     if(Obj[users][Ids] == undefined) {
         delete Obj[users];
     }
 }

我得到这个错误:

User[users][Ids].splice(0, 1) is not a function

如何只拼接我正在寻址的数组元素，而不拼接完整的 user2 数组？

Answer 1

使用 array.prototye.filter 从数组中删除用户，并使用 delete 删除整个用户数组，以防没有剩余元素:

var obj = {
    "User": {
        "user1": [
          {
            "desc": "NG60",
            "Id": 3473631702,
            "Status": "offline"
          }
        ],
        "user2": [
          {
            "desc": "somevalue",
            "Id": 963346121,
            "Status": "offline"
          },
          {
            "desc": "othervalue",  // SPLICE THIS OUT
            "Id": 963346122,      // SPLICE THIS OUT
            "Status": "offline"  // SPLICE THIS OUT
          }
        ],
        "user3": [
          {
            "desc": "whatever",
            "Id": 972878784
          }
        ]
      }
    };

function deleteUser(id) {
    Object.keys(obj.User).forEach(user => {
        obj.User[user] = obj.User[user].filter(u => u.Id !== id);
        if (obj.User[user].length === 0) {
            delete obj.User[user];
        }  
    });
}
deleteUser(963346121);
console.log(obj);
deleteUser(972878784);
console.log(obj);