Javascript 数组按多条件排序

Question

我有一个 JavaScript 数组，用于保存学生及其类(class)预约；

tablo[0] = ['Molly','Class3A','2018.12.18','13:50'];
tablo[1] = ['Ashley','Class4C','2018.10.14','14:50'];
tablo[2] = ['John','Class3A','2018.01.01','13:50'];
tablo[3] = ['Molly','Class3A','2018.11.20','13:50'];
tablo[4] = ['John','Class3A','2018.12.18','15:50'];
tablo[5] = ['Molly','Class3A','2018.09.11','13:50'];
tablo[6] = ['Ashley','Class4C','2018.10.14','15:50'];
tablo[7] = ['Ashley','Class4C','2018.11.12','13:50'];
tablo[8] = ['John','Class3A','2018.01.01','18:50'];
tablo[9] = ['John','Class3A','2018.01.01','10:50'];
tablo[10] = ['Molly','Class3A','2018.12.31','13:50'];
tablo[11] = ['Ashley','Class4C','2018.10.14','08:50'];
tablo[12] = ['Molly','Class3A','2018.05.07','13:50'];
tablo[13] = ['John','Class3A','2018.01.01','07:50'];
tablo[14] = ['Molly','Class3A','2018.09.11','12:50'];
tablo[15] = ['Molly','Class3A','2018.09.11','15:50'];
tablo[16] = ['Ashley','Class4C','2018.11.12','10:50'];

我想首先按类(class)名称排序该数组，然后按学生姓名排序，然后按日期排序，最后按小时排序。排序后的数组必须是这样的；

tablo[0] = ['John','Class3A','2018.01.01','07:50'];
tablo[1] = ['John','Class3A','2018.01.01','10:50'];
tablo[2] = ['John','Class3A','2018.01.01','13:50'];
tablo[3] = ['John','Class3A','2018.01.01','18:50'];
tablo[4] = ['John','Class3A','2018.12.18','15:50'];
tablo[5] = ['Molly','Class3A','2018.05.07','13:50'];
tablo[6] = ['Molly','Class3A','2018.09.11','12:50'];
tablo[7] = ['Molly','Class3A','2018.09.11','13:50'];
tablo[8] = ['Molly','Class3A','2018.09.11','15:50'];
tablo[9] = ['Molly','Class3A','2018.11.20','13:50'];
tablo[10] = ['Molly','Class3A','2018.12.18','13:50'];
tablo[11] = ['Molly','Class3A','2018.12.31','13:50'];
tablo[12] = ['Ashley','Class4C','2018.10.14','08:50'];
tablo[13] = ['Ashley','Class4C','2018.10.14','14:50'];
tablo[14] = ['Ashley','Class4C','2018.10.14','15:50'];
tablo[15] = ['Ashley','Class4C','2018.11.12','10:50'];
tablo[16] = ['Ashley','Class4C','2018.11.12','13:50'];

有很多方法可以按 2 个条件排序，但是我无法克服按 4 个条件排序的问题，如上面的示例。

Answer 1

试试这个

tablo.sort( (a,b)=> a[1].localeCompare(b[1]) || a[0].localeCompare(b[0]) ||
                    a[2].localeCompare(b[2]) || a[3].localeCompare(b[3])    );

tablo = [];

tablo[0] = ['Molly','Class3A','2018.12.18','13:50'];
tablo[1] = ['Ashley','Class4C','2018.10.14','14:50'];
tablo[2] = ['John','Class3A','2018.01.01','13:50'];
tablo[3] = ['Molly','Class3A','2018.11.20','13:50'];
tablo[4] = ['John','Class3A','2018.12.18','15:50'];
tablo[5] = ['Molly','Class3A','2018.09.11','13:50'];
tablo[6] = ['Ashley','Class4C','2018.10.14','15:50'];
tablo[7] = ['Ashley','Class4C','2018.11.12','13:50'];
tablo[8] = ['John','Class3A','2018.01.01','18:50'];
tablo[9] = ['John','Class3A','2018.01.01','10:50'];
tablo[10] = ['Molly','Class3A','2018.12.31','13:50'];
tablo[11] = ['Ashley','Class4C','2018.10.14','08:50'];
tablo[12] = ['Molly','Class3A','2018.05.07','13:50'];
tablo[13] = ['John','Class3A','2018.01.01','07:50'];
tablo[14] = ['Molly','Class3A','2018.09.11','12:50'];
tablo[15] = ['Molly','Class3A','2018.09.11','15:50'];
tablo[16] = ['Ashley','Class4C','2018.11.12','10:50'];

tablo.sort( (a,b)=> a[1].localeCompare(b[1]) || a[0].localeCompare(b[0]) ||
                    a[2].localeCompare(b[2]) || a[3].localeCompare(b[3]) );

console.log(tablo.map(x=>x.join(' ')));