javascript - 搜索和过滤数组

Question

假设我有一个这样的数组:

var arr = ['hello, my', 'hello, my name is', 'hello, my name is newton', 'hello, his', 'hello, his name is', 'hello, his name is pluto', 'hello, she is britney'];

我想过滤成:

var arr = ['hello, my name is newton', 'hello, his name is pluto', 'hello, she is britney'];

我不知道怎么说，但条件是如果一个数组元素的字符串可以在其他元素上找到，那么它应该被删除。像 'hello, my' 可以在紧接着的下一个元素 'hello, my name is' 中找到，所以 'hello, my' 应该被删除。

我要过滤的实际数组是:

var arr = ['11 22 13', '11 22 13 34', '11 22 13 34 15', '11 22 13 34 35', '11 22 23', '11 22 23 34', '11 22 23 34 15', '11 22 23 34 35', '31 22 13', '31 22 13 34', '31 22 13 34 15', '31 22 13 34 35', '31 22 23', '31 22 23 34', '31 22 23 34 15', '31 22 23 34 35'];

我试图将它分成不同的组，但我仍然不知道如何处理它。无论如何我都会展示它:

var threelink = [];
var fourlink = [];
var fivelink = [];

    for(var i=0; i < arr.length; i++){
        if(arr[i].length>8&&arr[i].length<12){
            fourlink.push(arr[i]);
        }
        else if(arr[i].length>11){
            fivelink.push(arr[i]);
        }
        else { 
            threelink.push(arr[i]);
        }
    }

Answer 1

我猜你想

arr.filter(function(e, i, a) {
  return !a.some(function(e2) {
    return e2 !== e && e2.includes(e);
  });
})

这表示过滤数组，只保留没有(!some)其他元素包含它(但不等于它)的元素。

使用 ES6 箭头函数更紧凑一些:

arr.filter((e, i, a) => !a.some(e2 => e2 !== e && e2.includes(e)));

var arr = ['hello, my', 'hello, my name is', 'hello, my name is newton', 'hello, his', 'hello, his name is', 'hello, his name is pluto', 'hello, she is britney'];

var filtered = arr.filter((e, i, a) => !a.some(e2 => e2 !== e && e2.includes(e)));

console.log(filtered);