JavaScript - 删除两个数组之间的多个相同值

Question

我目前正在编写一段代码，我需要比较两个数组并删除多个具有相同名称的元素。这是数组；

vacant = [
"FRAMIA420.2 - 0h 36 m",
"FRAMIA510.4 - 0h 36 m",
"FRAMIA320.7 - 0h 36 m",
"FRAMIA520.7 - 0h 36 m",
"FRAMIA450.3 - 1h 36 m",
"FRAMIA350.1 - 2h 21 m",
"FRAMIA210.2 - 2h 21 m",
"FRAMIA340.2 - 2h 36 m"]

booked = [
"FRAMIA440.5 - 13h 0 m",
"FRAMIA540.2 - 3h 45 m",
"FRAMIA340.2 - 5h 45 m",
"FRAMIA250.1 - 3h 45 m",
"FRAMIA420.2 - 3h 45 m",
"FRAMIA540.1 - 13h 0 m",
"FRAMIA520.5 - 3h 45 m",
"FRAMIA240.4 - 3h 45 m",
"FRAMIA510.2 - 7h 0 m",
"FRAMIA510.4 - 2h 45 m",
"FRAMIA520.7 - 2h 45 m",
"FRAMIA450.1 - 1h 45 m",
"FRAMIA450.3 - 2h 0 m"]

所以这两个数组之间相似的元素是:FRAMIA420.2, FRAMIA510.4, FRAMIA520.7, FRAMIA450 .3 和FRAMIA340.2

我已经过滤掉了元素的时间戳部分，所以我只需要比较名称部分；

var firstPart = [];
vacant.forEach(function (obj1) {
    firstPart.push(obj1.substring(0, obj1.indexOf('-')))
});
booked.forEach(function (obj2) {
    var c = firstPart.indexOf(obj2.substring(0, obj2.indexOf('-')));
});

最终结果应该是这样的，只留下 vacant 数组中的元素，与 booked 数组没有相似之处:

FRAMIA320.7 - 0h 36 m
FRAMIA350.1 - 2h 21 m
FRAMIA210.2 - 2h 21 m

请注意，数组之间的相似度每天都在变化，有时可能有 2 个相似元素，而其他日子可能有 8 个或更多。

有什么快速有效的方法吗？

Answer 1

您可以在 booked 数组中构造一个包含所有姓名的列表，然后遍历空数组，检查该姓名是否在已预订姓名列表中。

vacant = [
  "FRAMIA420.2 - 0h 36 m",
  "FRAMIA510.4 - 0h 36 m",
  "FRAMIA320.7 - 0h 36 m",
  "FRAMIA520.7 - 0h 36 m",
  "FRAMIA450.3 - 1h 36 m",
  "FRAMIA350.1 - 2h 21 m",
  "FRAMIA210.2 - 2h 21 m",
  "FRAMIA340.2 - 2h 36 m"
]

booked = [
  "FRAMIA440.5 - 13h 0 m",
  "FRAMIA540.2 - 3h 45 m",
  "FRAMIA340.2 - 5h 45 m",
  "FRAMIA250.1 - 3h 45 m",
  "FRAMIA420.2 - 3h 45 m",
  "FRAMIA540.1 - 13h 0 m",
  "FRAMIA520.5 - 3h 45 m",
  "FRAMIA240.4 - 3h 45 m",
  "FRAMIA510.2 - 7h 0 m",
  "FRAMIA510.4 - 2h 45 m",
  "FRAMIA520.7 - 2h 45 m",
  "FRAMIA450.1 - 1h 45 m",
  "FRAMIA450.3 - 2h 0 m"
]

function getName(str) {
  return str.substring(0, str.indexOf('-'));
}

var bookedNames = [];
booked.forEach(function (bookedStr) {
  bookedNames.push(getName(bookedStr))
});

var uniqueVacant = [];
vacant.forEach(function (vacantStr) {
  var vacantName = getName(vacantStr);
  if (!bookedNames.includes(vacantName))
    uniqueVacant.push(vacantStr)
});
console.log(uniqueVacant);