python - 查找路径的根

Question

我有一条路:

path = foo/bar/baz

我想确定基数是什么。在此示例中，它应该返回 “foo”。

我试过几种方法:

root = re.search('(.+?)/(.+)', path).group(1)

paths = path.split('/')[0]
root = paths[0] if paths[0] or len(paths) <= 1 else '/'.join(paths[0:2])

def rootname(path):
  head,tail = os.path.split(path)
  if head != '':
   return rootname(head)
  else:
   return path
root = rootname(path)

是否有更“Pythonic”的方式来访问根目录？

即

root = os.path.''rootname''(path)

Answer 1

>>> import os
>>> path = '/foo/bar/baz'
>>> path = path.lstrip(os.sep)  # Get rid of leading "/" if any
>>> root = path[:path.index(os.sep)] if os.sep in path else path
>>> root
'foo'