我正在尝试在 sequelize 上实现这个 mysql 命令,但就我是使用这个库的新手而言,我无法实现它
我想做这个sql命令:
SELECT * FROM users
join users_contacts_lists on users_contacts_lists.mobile_number = users.mobile_number
WHERE users_contacts_lists.user_id = 1
我创建数据库模式的模型:
'use strict';
var config = require('../config');
var User = config.sequelize.define('users', {
id: {
type: config.Sequelize.INTEGER,
autoIncrement: true,
primaryKey: true
},
password: {
type: config.Sequelize.STRING
},
username: {
type: config.Sequelize.STRING
},
mobileNumber: {
type: config.Sequelize.STRING,
field: 'mobile_number'
},
status: {
type: config.Sequelize.STRING
},
}, {freezeTableName: true});
var UsersContactsLists = config.sequelize.define('users_contacts_lists', {
id: {
type: config.Sequelize.INTEGER,
autoIncrement: true,
primaryKey: true
},
userId: {
type: config.Sequelize.INTEGER,
field: 'user_id'
},
mobileNumber: {
type: config.Sequelize.STRING,
field: 'mobile_number', defaultValue: 0
}
}, {freezeTableName: true});
UsersContactsLists.belongsTo(ChannelsTypes, {foreignKey: 'user_id'});
User.hasMany(Channels, {foreignKey: 'id'});
User.sync();
UsersContactsLists.sync();
module.exports =
{
users: User,
usersContactsLists: UsersContactsLists
};
我该如何解决这个问题?提前致谢
最佳答案
您可以在这样的关系中定义目标键和外键:
User.belongsTo(UsersContactsLists, {targetKey:'mobileNumber',foreignKey: 'mobileNumber'});
然后你可以使用这个:
User.findAll({
include: [{
model: UsersContactsLists,
where: {
userId: 1
}
}]
})
关于javascript - Nodejs 在 sequelize 上对两个表使用 JOIN,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40728509/