javascript - AJAX POST 不起作用

Question

我无法让我的代码工作。我想将“next_question_id”按钮的内容发送到我的 php 文件 next_question.php。然后在 div“question_text”中显示输出。我做错了什么..:)

Javascript

  function myFunction(clicked_id) {
    var button = clicked_id
    var next_question_id = document.getElementById(button).getAttribute("next_question_id");
    $.post('next_question.php', {
        postnextquestionid: next_question_id
      },
      function(data) {
        $('#question_text').html(data);
      });

  }

PHP

<?php
include 'conn.php';
$next_question_id = $_POST['next_question_id'];
echo $next_question_id;
?>

Answer 1

您的帖子 var 将是 postnextquestionid，而不是 next_question_id

$next_question_id = $_POST['postnextquestionid'];