python : How to compare strings and ignore white space and special characters

Question

我想比较两个字符串，这样比较应该忽略特殊字符的差异。也就是说，

Hai, this is a test

应该匹配

Hai ! this is a test "or" Hai this is a test

有没有办法在不修改原始字符串的情况下做到这一点？

Answer 1

这会在进行比较之前删除标点符号和空格:

In [32]: import string

In [33]: def compare(s1, s2):
    ...:     remove = string.punctuation + string.whitespace
    ...:     return s1.translate(None, remove) == s2.translate(None, remove)

In [34]: compare('Hai, this is a test', 'Hai ! this is a test')
Out[34]: True