我试图将结果或函数 runcmd 保存在变量 Result 中。 这是我尝试过的: 导入子进程
def runcmd(cmd):
x = subprocess.Popen(cmd, stdout=subprocess.PIPE)
Result = x.communicate(stdout)
return Result
runcmd("dir")
当我运行这些代码时,我得到了这个结果:
Traceback (most recent call last):
File "C:\Python27\MyPython\MyCode.py", line 7, in <module>
runcmd("dir")
File "C:\Python27\MyPython\MyCode.py", line 4, in runcmd
x = subprocess.Popen(cmd, stdout=subprocess.PIPE)
File "C:\Python27\lib\subprocess.py", line 679, in __init__
errread, errwrite)
File "C:\Python27\lib\subprocess.py", line 893, in _execute_child
startupinfo)
WindowsError: [Error 2] The system cannot find the file specified
我该怎么做才能解决这个问题?
最佳答案
我想你要找的是 os.listdir()
查看 os module了解更多信息
一个例子:
>>> import os
>>> l = os.listdir()
>>> print (l)
['DLLs', 'Doc', 'google-python-exercises', 'include', 'Lib', 'libs', 'LICENSE.txt', 'NEWS.txt', 'python.exe', 'pythonw.e
xe', 'README.txt', 'tcl', 'Tools', 'VS2010Cmd.lnk']
>>>
您还可以将输出读入列表:
result = []
process = subprocess.Popen('dir',
shell=True,
stdout=subprocess.PIPE,
stderr=subprocess.PIPE )
for line in process.stdout:
result.append(line)
errcode = process.returncode
for line in result:
print(line)
关于python - 如何在 Windows 中使用子进程,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19819417/