python - 如何使用 Python 仅打印 csv 文件的前 10 行？

Question

我是 Python 的新手，我只想打印一个巨大的 csv 文件的前 10 行。

到目前为止，这是我的代码，用于打印 csv 文件中的所有行

import csv
with open('titanic.csv') as csvfile:
    reader = csv.DictReader(csvfile)
    for row in reader:
        print(row['survived'], row['pclass'], row['name'], row['sex'], row['age'])

Answer 1

使用itertools.islice:

import csv
from itertools import islice

with open('titanic.csv') as csvfile:
    reader = csv.DictReader(csvfile)
    for row in islice(reader, 10): # first 10 only
        print(row['survived'], row['pclass'], row['name'], row['sex'], row['age'])

同时，您还可以使用 operator.itemgetter 使列变得更容易一些:

import csv
from itertools import islice
from operator import itemgetter

get_columns = itemgetter('survived', 'pclass', 'name', 'sex', 'age')

with open('titanic.csv') as csvfile:
    reader = csv.DictReader(csvfile)
    for row in islice(reader, 10): # first 10 only
        print(*get_columns(row))