我正在尝试使用 js ajax 在数据库中插入多个数据，但它不起作用，当我尝试仅插入一个数据时，它成功地工作
这是我的indexa.php
<html>
<head>
<script type="text/javascript">
function insert() {
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
} else{
xmlhttp = new ActionXObject('Microsoft.XMLHTTP');
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById('success_failed_msg').innerHTML = xmlhttp.responseText;
} else {
console.log("faliled");
}
}
parameters = 'first_name='+document.getElementById('firstName').value;
console.log(parameters);
xmlhttp.open('POST','insert.inc.php',true);
xmlhttp.setRequestHeader('Content-type','application/x-www-form-urlencoded');
xmlhttp.send(parameters);
}
</script>
</head>
<body>
First Name : <input type="text" id="firstName"><br/><br/>
Last Name : <input type="text" id="lastName"><br/><br/>
Username : <input type="text" id="userName"><br/><br/>
Password : <input type="password" id="password"><br/><br/>
Re-type Password : <input type="password" id="retypePassword"><br/><br/>
<input type="button" value="Submit" onclick="insert()">
<div id="success_failed_msg"></div>
</body>
</html>
我的 include.inc.php
if (isset($_POST['first_name'])) {
$firstname = $_POST['first_name'];
if (!empty($firstname)) {
$insert_select = "INSERT INTO ajax_member_data(`first_name`) VALUES('".mysqli_real_escape_string($db_connect,$firstname)."')";
if ($insert_query_run = mysqli_query($db_connect,$insert_select)) {
echo 'Data inserted successfully';
} else {
echo 'Failed';
}
} else {
echo 'Please enter the value';
}
}
当我尝试这个脚本时
<script type="text/javascript">
function insert() {
if (window.XMLHttpRequest) {
xmlhttp = new XMLHttpRequest();
} else{
xmlhttp = new ActionXObject('Microsoft.XMLHTTP');
}
xmlhttp.onreadystatechange = function() {
if (xmlhttp.readyState == 4 && xmlhttp.status == 200) {
document.getElementById('success_failed_msg').innerHTML = xmlhttp.responseText;
} else {
console.log("faliled");
}
}
parameters = 'first_name='+document.getElementById('firstName').value'&last_name='+document.getElementById('lastName').value'&username='+document.getElementById('userName').value'&password='+document.getElementById('password').value'&retype_password='+document.getElementById('retypePassword').value;
console.log(parameters);
xmlhttp.open('POST','insert.inc.php',true);
xmlhttp.setRequestHeader('Content-type','application/x-www-form-urlencoded');
xmlhttp.send(parameters);
}
</script>
我的 include.inc.php
if (isset($_POST['first_name']) && isset($_POST['last_name']) && isset($_POST['username']) && isset($_POST['password']) && isset($_POST['retype_password'])) {
$firstname = $_POST['first_name'];
$lastname = $_POST['last_name'];
$usrname = $_POST['username'];
$password = $_POST['password'];
$retype_password = $_POST['retype_password'];
if (!empty($firstname) && !empty($lastname) && !empty($usrname) && !empty($password) && !empty($retype_password)) {
$insert_select = "INSERT INTO ajax_member_data(`first_name`,`last_name`,`user_name`,`password`) VALUES('".mysqli_real_escape_string($db_connect,$firstname)."', '".mysqli_real_escape_string($db_connect,$lastname)."', '".mysqli_real_escape_string($db_connect,$usrname)."', '".mysqli_real_escape_string($db_connect,$password)."')";
if ($insert_query_run = mysqli_query($db_connect,$insert_select)) {
echo 'Data inserted successfully';
} else {
echo 'Failed';
}
} else {
echo 'Please enter the value';
}
}
最佳答案
你没有正确地连接。看这里，
parameters = 'first_name='+document.getElementById('firstName').value'&last_name='+document.getElementById('lastName').value'&username='+document.getElementById('userName').value'&password='+document.getElementById('password').value'&retype_password='+document.getElementById('retypePassword').value;
^ missing + ^ missing + ^ missing + ^ missing +
应该是，
parameters = 'first_name='+document.getElementById('firstName').value+'&last_name='+document.getElementById('lastName').value+'&username='+document.getElementById('userName').value+'&password='+document.getElementById('password').value+'&retype_password='+document.getElementById('retypePassword').value;
旁注:了解 prepared statements因为现在您的查询容易受到 SQL 注入(inject)的影响。另见 how you can prevent SQL injection in PHP .
关于javascript - 多个值在 js ajax 中不起作用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/40245085/