javascript - 如何保留对象的某些属性？

Question

我有这个对象。如果某个属性的值为 null，我将删除该属性。但我有一些特殊属性，我想无论如何(即使它们的值为空)。到目前为止，我的代码运行良好，但我不喜欢必须反复使用 OR || 运算符这一事实。 示例:

key === 'alwaysCountWithMe' || key === 'ABC' || key ==='doNotDeleteMe' || key === 'specialProperty'

这是我的代码:

var object = {
  "firstname": null,
  "lastname": "White",
  "ABC": null,
  "hobby": null,
  "c": 3,
  "alwaysCountWithMe": null,
  "doNotDeleteMe": null,
  "specialProperty": null,
};

console.log(_.pickBy(object, (value, key) => !!value || key === 'alwaysCountWithMe' || key === 'ABC' || key === 'doNotDeleteMe' || key === 'specialProperty'));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>

是否有一种更简洁的方法可以做到这一点，而不必一遍又一遍地使用 ||？

Answer 1

使用key数组一直保留，检查是否includes(key):

var object = {
  "firstname": null,
  "lastname": "White",
  "ABC": null,
  "hobby": null,
  "c": 3,
  "alwaysCountWithMe": null,
  "doNotDeleteMe": null,
  "specialProperty": null,
};
const alwaysKeep = ['alwaysCountWithMe', 'ABC', 'doNotDeleteMe', 'specialProperty'];

console.log(_.pickBy(object, (value, key) => !!value || alwaysKeep.includes(key)));

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>