给定一个单词,它可能是也可能不是单数形式的名词,你将如何生成它的复数形式?
基于此NLTK tutorial还有这个informal list关于复数规则,我写了这个简单的函数:
def plural(word):
"""
Converts a word to its plural form.
"""
if word in c.PLURALE_TANTUMS:
# defective nouns, fish, deer, etc
return word
elif word in c.IRREGULAR_NOUNS:
# foot->feet, person->people, etc
return c.IRREGULAR_NOUNS[word]
elif word.endswith('fe'):
# wolf -> wolves
return word[:-2] + 'ves'
elif word.endswith('f'):
# knife -> knives
return word[:-1] + 'ves'
elif word.endswith('o'):
# potato -> potatoes
return word + 'es'
elif word.endswith('us'):
# cactus -> cacti
return word[:-2] + 'i'
elif word.endswith('on'):
# criterion -> criteria
return word[:-2] + 'a'
elif word.endswith('y'):
# community -> communities
return word[:-1] + 'ies'
elif word[-1] in 'sx' or word[-2:] in ['sh', 'ch']:
return word + 'es'
elif word.endswith('an'):
return word[:-2] + 'en'
else:
return word + 's'
但我认为这是不完整的。有更好的方法吗?
最佳答案
pattern-en 包提供 pluralization
>>> import pattern.en
>>> pattern.en.pluralize("dog")
'dogs'
>>>
关于python - 生成名词的复数形式,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/18902608/