javascript - 为什么我的 javascript 函数没有返回 true？

Question

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Answer 1

请改成Array.prototype.some()

The some() method tests whether some element in the array passes the test implemented by the provided function.

function isInSupplier(idsupplier) {
    return suppliers.some(function(object) {
        if (object._id == idsupplier) {
            console.log("TRUE");
            return true;
        };
    });
}

或者没有控制台输出

function isInSupplier(idsupplier) {
    return suppliers.some(function(object) {
        return object._id == idsupplier;
    });
}