Javascript 获取类实例的名称

Question

function myClass(a,b,c) {
     this.alertMyName=function(){alert(instancename)}

{...}


}

然后

foo = myClass(a,b,c);
boo = myClass(a,b,c);

foo.alertMyName(); //it should alert 'foo'
boo.alertMyName(); //it should alert 'boo'

在实践中，对于创建大量 html 对象的类，我需要它来为它们的 ID 添加前缀，以将它们与此类的另一个实例创建的同一对象区分开来。

Answer 1

我在 Stack Overflow 上找不到解决方案，所以这是我从 ronaldcs 找到的解决方案在 dforge.net 上: http://www.dforge.net/2013/01/27/how-to-get-the-name-of-an-instance-of-a-class-in-javascript/

myObject = function () {
  this.getName = function () {
    // search through the global object for a name that resolves to this object
    for (var name in window)
      if (window[name] == this)
        return name;
  };
};

试一试:

var o = new myObject(); 
alert(o.getName()); // alerts "o"