javascript根据键值过滤嵌套对象

Question

我希望通过“step”键的值来过滤嵌套的 javascript 对象:

var data = {
"name": "Root",
"step": 1,
"id": "0.0",   
"children": [
    {
    "name": "first level child 1",
    "id": "0.1",
    "step":2,
    "children": [
        {
        "name": "second level child 1",
        "id": "0.1.1",
        "step": 3,
        "children": [
            {
            "name": "third level child 1",
            "id": "0.1.1.1",
            "step": 4,
            "children": []},
        {
            "name": "third level child 2",
            "id": "0.1.1.2",
            "step": 5,
            "children": []}

        ]},
                ]}
]

};

var subdata = data.children.filter(function (d) {
        return (d.step <= 2)});

这只会返回未修改的嵌套对象，即使我将过滤器的值设置为 1。 .filter 在嵌套对象上工作还是我需要在这里滚动我自己的函数，建议和正确的代码表示赞赏。

Answer 1

递归过滤器函数很容易创建。这是一个示例，它去除了定义的所有项目的 JS 对象 ["depth","x","x0","y","y0","parent","size"] :

function filter(data) {
  for(var i in data){
    if(["depth","x","x0","y","y0","parent","size"].indexOf(i) != -1){
       delete data[i]; 
    } else if (i === "children") {
      for (var j in data.children) {
        data.children[j] = filter(data.children[j])
      }
    }  
  }
  return data;
}

如果您想按其他内容进行过滤，只需使用您选择的过滤函数更新第二行。