我正在使用旧线程发布试图解决相同问题的新代码。 什么是安全 pickle ? this?
socks .py
from socket import socket
from socket import AF_INET
from socket import SOCK_STREAM
from socket import gethostbyname
from socket import gethostname
class SocketServer:
def __init__(self, port):
self.sock = socket(AF_INET, SOCK_STREAM)
self.port = port
def listen(self, data):
self.sock.bind(("127.0.0.1", self.port))
self.sock.listen(len(data))
while data:
s = self.sock.accept()[0]
siz, dat = data.pop()
s.send(siz)
s.send(dat)
s.close()
class Socket:
def __init__(self, host, port):
self.sock = socket(AF_INET, SOCK_STREAM)
self.sock.connect((host, port))
def recv(self, size):
return self.sock.recv(size)
包.py
#http://stackoverflow.com/questions/6234586/we-need-to-pickle-any-sort-of-callable
from marshal import dumps as marshal_dumps
from pickle import dumps as pickle_dumps
from struct import pack as struct_pack
class packer:
def __init__(self):
self.f = []
def pack(self, what):
if type(what) is type(lambda:None):
self.f = []
self.f.append(marshal_dumps(what.func_code))
self.f.append(pickle_dumps(what.func_name))
self.f.append(pickle_dumps(what.func_defaults))
self.f.append(pickle_dumps(what.func_closure))
self.f = pickle_dumps(self.f)
return (struct_pack('Q', len(self.f)), self.f)
解压.py
from types import FunctionType
from pickle import loads as pickle_loads
from marshal import loads as marshal_loads
from struct import unpack as struct_unpack
from struct import calcsize
#http://stackoverflow.com/questions/6234586/we-need-to-pickle-any-sort-of-callable
class unpacker:
def __init__(self):
self.f = []
self.fcompiled = lambda:None
self.sizeofsize = calcsize('Q')
def unpack(self, sock):
size = struct_unpack('Q', sock.recv(self.sizeofsize))[0]
self.f = pickle_loads(sock.recv(size))
a = marshal_loads(self.f[0])
b = globals() ##
c = pickle_loads(self.f[1])
d = pickle_loads(self.f[2])
e = pickle_loads(self.f[3])
self.fcompiled = FunctionType(a, b, c, d, e)
return self.fcompiled
测试.py
from unpack import unpacker
from pack import packer
from sock import SocketServer
from sock import Socket
from threading import Thread
from time import sleep
count = 2
port = 4446
def f():
print 42
def server():
ss = SocketServer(port)
pack = packer()
functions = [pack.pack(f) for nothing in range(count)]
ss.listen(functions)
if __name__ == "__main__":
Thread(target=server).start()
sleep(1)
unpack = unpacker()
for nothing in range(count):
print unpack.unpack(Socket("127.0.0.1", port))
输出:
<function f at 0x12917d0>
<function f at 0x12915f0>
最佳答案
我不认为 Process 对象设计为通过网络发送。查看 multiprocessing/process.py 中的第 256 行。
# We subclass bytes to avoid accidental transmission of auth keys over network.
我觉得这是有充分理由的。如果你想做分布式计算,也许你应该看看 library designed for that .
关于Python 分布式计算(有效),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/6212326/