我在将 base64 编码字符串转换为二进制时遇到问题。我正在以下链接中收集 Fingerprint2D,
url = "https://pubchem.ncbi.nlm.nih.gov/rest/pug/compound/cid/108770/property/Fingerprint2D/xml"
Fingerprint2D=AAADccB6OAAAAAAAAAAAAAAAAAAAAAAAAAA8WIEAAAAAAACxAAAAHgAACAAADAzBmAQwzoMABgCI AiTSSACCCAAhIAAAiAEMTMgMJibMsZuGeijn4BnI+YeQ0OMOKAACAgAKAABQAAQEABQAAAAAAAAA AA==
Pubchem中的descriptiong说这是115字节的字符串,转换成二进制应该是920位。我尝试使用以下命令将其转换为二进制文件,
response = requests.get(url)
tree = ET.fromstring(response.text)
for el in tree[0]:
if "Fingerprint2D" in el.tag:
fpp = bin(int(el.text, 16))
print(len(fpp))
如果我使用上面的代码,我会收到以下错误,“值错误:使用 base16 的 int() 的无效文字:
如果我使用下面的代码,fpp(二进制)的长度等于 1278,这不是我所期望的。
response = requests.get(url)
tree = ET.fromstring(response.text)
for el in tree[0]:
if "Fingerprint2D" in el.tag:
fpp = bin(int(hexlify(el.text), 16))
print(len(fpp))
非常感谢!!
最佳答案
要解码 base64 格式,您需要将 bytes
对象传递给 base64.decodebytes
函数:
import base64
t = "AAADccB6OAAAAAAAAAAAAAAAAAAAAAAAAAA8WIEAAAAAAACxAAAAHgAACAAADAzBmAQwzoMABgCI AiTSSACCCAAhIAAAiAEMTMgMJibMsZuGeijn4BnI+YeQ0OMOKAACAgAKAABQAAQEABQAAAAAAAAA AA==".encode("ascii")
decoded = base64.decodebytes(t)
print(decoded)
print(len(decoded)*8)
我得到以下信息:
b'\x00\x00\x03q\xc0z8\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00\x00<X\x81\x00\x00\x00\x00\x00\x00\xb1\x00\x00\x00\x1e\x00\x00\x08\x00\x00\x0c\x0c\xc1\x98\x040\xce\x83\x00\x06\x00\x88\x02$\xd2H\x00\x82\x08\x00! \x00\x00\x88\x01\x0cL\xc8\x0c&&\xcc\xb1\x9b\x86z(\xe7\xe0\x19\xc8\xf9\x87\x90\xd0\xe3\x0e(\x00\x02\x02\x00\n\x00\x00P\x00\x04\x04\x00\x14\x00\x00\x00\x00\x00\x00\x00\x00'
920
所以 920 位符合预期。
要获取二进制数据,只需迭代字节并使用 format
和零填充到 8 位(bin
添加 0b
header 所以它不合适),然后 join
字符串:
print("".join(["{:08b}".format(x) for x in decoded]))
结果:
00000000000000000000001101110001110000000111101000111000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000011110001011000100000010000000000000000000000000000000000000000000000001011000100000000000000000000000000011110000000000000000000001000000000000000000000001100000011001100000110011000000001000011000011001110100000110000000000000110000000001000100000000010001001001101001001001000000000001000001000001000000000000010000100100000000000000000000010001000000000010000110001001100110010000000110000100110001001101100110010110001100110111000011001111010001010001110011111100000000110011100100011111001100001111001000011010000111000110000111000101000000000000000001000000010000000000000101000000000000000000101000000000000000001000000010000000000000101000000000000000000000000000000000000000000000000000000000000000000
(如预期的那样是 920 个字符)
关于Python从base64转换为二进制,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43207978/