我必须在我的按钮点击事件中编写上面的代码。网络服务工作正常。网络服务方法返回一个字符串。 thatString 等于成功转到下一个布局。它工作正常。但其他部分不起作用。 toast 抛出异常
final SoapSerializationEnvelope envelope1 = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope1.setOutputSoapObject(request1);
//msg.setText("hi");
envelope1.dotNet = true;
final Thread webser=new Thread(){
public void run()
{
try {
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
System.out.println("four and Object value is : " +androidHttpTransport);
System.out.println("four and URL : " +URL);
//this is the actual part that will call the webservice
androidHttpTransport.call(SOAP_ACTION, envelope1);
System.out.println("four a");
// Get the SoapResult from the envelope body.
SoapObject result1 = (SoapObject)envelope1.bodyIn;
if(result1 != null)
{
//Get the first property and change the label text
status=result1.getProperty(0).toString();
if(status.equalsIgnoreCase("success"))
{
Intent home=new Intent(LoginActivity.this,MainActivity.class);
startActivity(home);
}
else
{
Thread.sleep(1000);
Toast.makeText(LoginActivity.this,"Enter Valid Username/Password", Toast.LENGTH_LONG).show();
}
}
else
{
System.out.println("nodata");
}
} catch (Exception e) {
e.printStackTrace();
System.out.println("Exception" +e);
}
}
};
webser.start();
}
});
最佳答案
您正在从后台线程访问UI。从 Thread 修改 UI 像这样使用..
LoginActivity.this.runOnUiThread(new run Runnable() {
@Override
public void run() {
Toast.makeText(LoginActivity.this,"Enter Valid Username/Password", Toast.LENGTH_LONG).show();
}
});
并且不要捕获(Exception e)。这是糟糕的编程习惯。 :)
关于android - 无法处理 webservice 方法调用中的线程？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/11809276/