android - 如何解析内部 json 对象数组

Question

我正在使用 ESPN Sports API。任何人都可以帮助我如何解析这个吗？

我正在粘贴我的代码，我只能解析名称和 ID——请帮助如何解析内部对象项。

public class BaseballActivity extends ListActivity{

private static String url = "http://api.espn.com/v1/sports/baseball?apikey=h29yphwtf7893hktfbn7cd5g";

private static final String TAG_SPORTS = "sports";
private static final String TAG_ID = "id";
private static final String TAG_TIMESTAMP = "timestamp";
private static final String TAG_NAME = "name";
private static final String TAG_NEWS = "news";
private static final String TAG_HEADLINES = "headlines";
private static final String TAG_LINKS = "links";
private static final String TAG_API = "api";
private static final String TAG_SPORTS1 = "sports";
private static final String TAG_HREF = "href";

JSONArray sports = null;

@Override
public void onCreate(Bundle savedInstanceState) {


    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    // HashMap for ListView

    ArrayList<HashMap<String, String>> sportsList = new ArrayList<HashMap<String, String>>();

    // creating Json parser instance
    JSONParser jParser = new JSONParser();

    // getting Json String from url

    JSONObject json = jParser.getJSONFromUrl(url);

    try{
        // Getting Array of Contacts
                    sports = json.getJSONArray(TAG_SPORTS);

                    // looping through All Contacts
                    for(int i = 0; i < sports.length(); i++){
                        JSONObject c = sports.getJSONObject(i);


            //String news = c.getString(TAG_NEWS);
           // String headlines = c.getString(TAG_HEADLINES);
            String name = c.getString(TAG_NAME);
           // String timestamp = c.getString(TAG_TIMESTAMP);
            String id = c.getString(TAG_ID);

         //   JSONObject links = c.getJSONObject(TAG_LINKS);
          //  JSONObject api = c.getJSONObject(TAG_API);
          //  JSONObject sports = c.getJSONObject(TAG_SPORTS1);

         //   String href = c.getString(TAG_HREF);



            HashMap<String, String> map = new HashMap<String, String>();

         //  map.put(TAG_TIMESTAMP, timestamp);
            map.put(TAG_NAME, name);
           // map.put(TAG_NEWS, news);
           // map.put(TAG_HEADLINES, headlines);
            map.put(TAG_ID, id);
         //   map.put(TAG_HREF, href);
            sportsList.add(map);
         }
    }
        catch (JSONException e) {
            e.printStackTrace();    

        }


    ListAdapter adapter = new SimpleAdapter(this, sportsList,
            R.layout.list_item,
            new String[]{TAG_NAME,TAG_ID} , new int[] {
            R.id.id,R.id.name});

   setListAdapter(adapter);   
 }
}

这是我正在使用的链接

Sample Link

Answer 1

我建议您使用 gson .对我来说，与...一起工作要容易得多。

编辑:(一些示例代码)

1. 下载 gson-2.2.2.jar 并将其添加到您的依赖项

2. 创建一个基类(当您使用多个请求时)

   public abstract class RequestBase {
   
   public String ToJson(){
       Gson gson = new Gson();
       return gson.toJson(this);
   }
   
   public abstract String getUrl();
   
   protected String getBaseUrl(){
       return //Your URL;
   }   
   }
   

3. 创建一个类来执行您的请求..

4. 为请求和响应创建类。然后你可以用 getters 和 setters 输入它们:

   公共(public)类 SomeRequest 扩展 RequestBase { @SerializedName("参数1") private int Parameter1;

   public void setParameter1(int Parameter1) {
       this.Parameter1= Parameter1;
   }
   
   public int getParameter1() {
       return Parameter1;
   }
   
   @Override
   public String getUrl() {
       return this.getBaseUrl() +"YOUR/OWN/URL" + Parameter1;
   }
   }
   

和

public class SomeResponse {
@SerializedName("responseParameter1")
private int responseParameter1;

@SerializedName("responseParameter2")
private String responseParameter2;

public void setResponseParameter1(int responseParameter1) {
    this.responseParameter1= responseParameter1;
}

public int getResponseParameter1() {
    return responseParameter1;
}

public void setResponseParameter2(String responseParameter2) {
    this.responseParameter2= responseParameter2;
}

public String getResponseParameter1() {
    return responseParameter2;
}
}