比方说我想用左右两列按钮创建一个相对 View 。
每个按钮恰好占据屏幕的 20%,以 10% 分隔,其余边框位于两侧。但是要为任何屏幕尺寸执行此操作。我认为 DP 行不通,因为您如何知道每个不同屏幕上的 DP 像素数?
基本上,您如何在所有设备之间保持 UI 的相对相同和适合?
最佳答案
简答:LinearLayout
。
长答案在这里:
Defining a percentage width for a LinearLayout?
也有在运行时获取密度的方法,但从长远来看,上述方法更容易。
准备好一些伪 xml!
<LinearLayout double fill parent, vertical>
<RelativeLayout w = 0, h = 0, weight smallish>
<Button A />
</RelativeLayout>
<LinearLayout w = 0, h = 0, weight largish. horizontal>
<!-- maybe you want these to be RelativeLayout and set the buttons
as centerHorizontalInParent="true" -->
<LinearLayout w = 0, h = 0, weight whatever 20% is>
<Buttons with some padding/margins>
</LinearLayout>
<Some kind of spacer, or just pad the LLs />
<LinearLayout repeat above />
</LL>
</LL>
编辑:
如果您一心想做很多动态调整大小,我有这个自定义类来获取屏幕大小:
public class ScreenGetter {
private float pixHeight;
private float pixWidth;
private float dpHeight;
private float dpWidth;
private float density;
public ScreenGetter (Context context){
Display display = ((WindowManager)
context.getSystemService(Context.WINDOW_SERVICE))
.getDefaultDisplay();
DisplayMetrics metrics = new DisplayMetrics ();
display.getMetrics(metrics);
pixHeight = metrics.heightPixels;
pixWidth = metrics.widthPixels;
density = context.getResources().getDisplayMetrics().density;
dpHeight = pixHeight / density;
dpWidth = pixWidth / density;
}
public float getPixHeight(){return pixHeight;}
public float getPixWidth(){return pixWidth;}
public float getDpHeight(){return dpHeight;}
public float getDpWidth(){return dpWidth;}
public float getDensity(){return density;}
}
显然,您需要做一些数学运算才能确定您想要的不同尺寸和密度的产品。您还需要考虑未使用的屏幕部分(ActionBar 等)
关于android - 使 UI 元素相对于屏幕尺寸?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/14574875/