请帮助我获取 BoxApi v2 for android 中当前用户的用户详细信息
我使用用户详细信息的代码如下:
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
super.onActivityResult(requestCode, resultCode, data);
BoxAndroidClient client = null;
if (Activity.RESULT_OK != AUTH_REQUEST) {
Toast.makeText(this, "fail", Toast.LENGTH_LONG).show();
} else {
BoxAndroidOAuthData oauth = data
.getParcelableExtra(OAuthActivity.BOX_CLIENT_OAUTH);
BoxAndroidOAuthData moath = data
.getParcelableExtra(OAuthActivity.USER_SERVICE);
client = new BoxAndroidClient(HelloWorldApplication.CLIENT_ID,
HelloWorldApplication.CLIENT_SECRET, null, null);
client.authenticate(oauth);
accestoken = oauth.getAccessToken().toString();
System.out.println("AUTHDATA" + oauth.getAccessToken().toString());// client.getUsersManager().getCurrentUser(requestObj).toString()
// + oauth.getAccessToken().toString());
BoxUser user = new BoxUser();
System.out.println("ID" + user.getId());
if (client == null) {
Toast.makeText(this, "fail", Toast.LENGTH_LONG).show();
} else {
((HelloWorldApplication) getApplication()).setClient(client);
Toast.makeText(this, "authenticated", Toast.LENGTH_LONG).show();
}
}
BoxDefaultRequestObject requestObject = null;
List<BoxUser> userList = null;
try {
userList = client.getUsersManager().getAllEnterpriseUser(
requestObject, null);
} catch (BoxRestException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (BoxServerException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (AuthFatalFailureException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
for (BoxUser usr : userList) {
System.out.println("Addr: " + usr.getAddress());
System.out.println("Name : " + usr.getName());
System.out.println("Login : " + usr.getLogin());
}
}
我得到的异常是 networkonmainthreadexception...
谁能帮帮我？
最佳答案
在原始 api 中获取当前用户信息是通过调用 GET/users/me 完成的
不确定在 Java 中是什么样子，但可能更像:
user = client.getUsersManager().getCurrentUser
关于android - 我想在 Box API v2 for Android 中检索当前用户的用户信息，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/21604594/