android - 如何在按下后停止 android Mx Player

Question

我有一个代码，当我第一次启动应用程序时它可以通过 mx 播放器显示视频，但没有任何错误，但是如果我关闭并再次打开应用程序，它说 Activity mx 播放器没有响应。我如何关闭 mx 播放器当我按后退按钮。 我的代码:

公共(public)类 MainActivity 扩展 Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    //setContentView(R.layout.activity_main);

    startMxPlayer(1, 1);
    finish();
}


private void startMxPlayer(int tuner, int ch) { 
    int port = 8000 + tuner * 10 + ch; 
    Uri uri = Uri.parse("udp://224.1." + (port & 0xff) + ".1:" + port); 
    Log.v("server", "udp://224.1." + (port & 0xff) + ".1:" + port); 
    Intent intent = new Intent(Intent.ACTION_VIEW, uri); 
    intent.setPackage( "com.mxtech.videoplayer.ad" );
    intent.putExtra("end_by","user");
    intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_NO_HISTORY); 
    getApplication().startActivity(intent); 
}

@Override
public boolean onCreateOptionsMenu(Menu menu) {
    // Inflate the menu; this adds items to the action bar if it is present.
    getMenuInflater().inflate(R.menu.main, menu);
    return true;
}

Answer 1

没有人可以停止终止进程，但我建议您以其他方式进行。

private void startMxPlayer(int tuner, int ch) { 
int port = 8000 + tuner * 10 + ch; 
Uri uri = Uri.parse("udp://224.1." + (port & 0xff) + ".1:" + port); 
Log.v("server", "udp://224.1." + (port & 0xff) + ".1:" + port); 

// add the following line.
ActivityManager.killBackgroundProcesses("com.mxtech.videoplayer.ad");

Intent intent = new Intent(Intent.ACTION_VIEW, uri); 
intent.setPackage( "com.mxtech.videoplayer.ad" );
intent.putExtra("end_by","user");
intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_NEW_TASK |         Intent.FLAG_ACTIVITY_NO_HISTORY); 
getApplication().startActivity(intent);