public void allButtonChoice(){
Button[] multiChoice = new Button[3];
multiChoice = new Button[]{choiceButton1,choiceButton2,choiceButton3,choiceButton4};
//to output shuffled array in an randomized order.
//Random number generator.
Random generateMultiChoice = new Random();
for(int i = 0; i < multiChoice.length; i++){
int randomPosition = generateMultiChoice.nextInt(multiChoice.length);
Button temp = multiChoice[i];
multiChoice[i] = multiChoice[randomPosition];
multiChoice[randomPosition] = temp;
}
//set the positions to the buttons in order
choiceButton1.setX(10f);
choiceButton1.setY(10f);
choiceButton2.setX(10f);
choiceButton2.setY(10f);
choiceButton3.setX(10f);
choiceButton3.setY(12f);
choiceButton4.setX(10f);
choiceButton4.setY(12f);
}
如何将变量分配给 choiceButton1、choiceButton2、choiceButton3 和 choiceButton4?是否可以用一个变量来保存四个带有 setX 和 setY 数据的按钮?
最佳答案
choiceButton1.setTag(值);
对你有用
可以调用getTag获取数据
关于java - Android 如何将变量分配给按钮?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/25800303/