java - JSON 解析过滤逗号分隔的记录

Question

第一个 JSON:

{
    "datas":[
        {
            "id":"1",
            "name":"Name 1",
            "users":"1,3"
        },
        {
            "id":"2",
            "name":"Name 2",
            "users":"2,5"
        }
    ]
}

第二个 JSON:

{
    "users":[
        {
            "id":"1",
            "name":"User 1"
        },
        {
            "id":"2"
            "name":"User 2"
        }
    ......
    ]
}

但无论我在哪里点击(名称 1 或名称 2)，我总是会获得所有用户的列表

这就是我用来仅根据 id 过滤用户的方法:

@Override
protected Boolean doInBackground(String... urls) {
    try {
        String[] strMultiUsers = strEventUsers.split(",");
        List<String> listMultiUsers = Arrays.asList(strMultiUsers);           

        HttpGet httppost = new HttpGet(urls[0]);
        HttpClient httpclient = new DefaultHttpClient();
        HttpResponse response = httpclient.execute(httppost);

        int status = response.getStatusLine().getStatusCode();

        if (status == 200) {
            HttpEntity entity = response.getEntity();
            String data = EntityUtils.toString(entity);


            JSONObject jsono = new JSONObject(data);
            JSONArray jarray = jsono.getJSONArray("users");

            for (int i = 0; i < jarray.length(); i++) {
                JSONObject object = jarray.getJSONObject(i);

                UsersList oldEventsList = new UsersList();

                oldEventsList.setId(object.getString("id"));                        
                oldEventsList.setName(object.getString("name"));

                if(listMultiUsers.contains(""))
                {

                }

                oldEventsArrayList.add(oldEventsList);
            }
            return true;
        }

我希望每当用户点击 Name 2 时，我只需要显示两个用户(用户 ID - 2 和 5)，但我仍然得到所有用户(1 到 5)

Answer 1

我找到了解决方案，并为其他开发人员放置:

String strUsers = object.getString("id").toString();
Log.d("users", strUsers);

usersList.setName(object.getString("name"));

if(listMultiUsers.contains(strUsers))
 {
     usersListArrayList.add(usersList);
 }