android - 根据 Random Textview 显示文本

Question

我在单击按钮时在两个 TextView 中显示随机文本。现在我必须在 textview2 中显示 textview1 中显示的文本的解释。但我无法得到它。我们将不胜感激。

我把文字放在string.xml中

<string name="one">1</string>
<string name="two">2</string>
<string name="three">3</string>
<string name="four">4</string>
<string name="five">5</string>
<string name="six">6</string>
<string name="seven">7</string>
<string name="eight">8</string>
<string name="nine">9</string>
<string name="ten">10</string>

<string name="one_explaination">This is number one</string>
<string name="two_explaination">This is number two</string>
<string name="three_explaination">This is number three</string>
<string name="four_explaination">This is number four</string>
<string name="five_explaination">This is number five</string>
<string name="six_explaination">This is number six</string>
<string name="seven_explaination">This is number seven</string>
<string name="eight_explaination">This is number eight</string>
<string name="nine_explaination">This is number nine</string>
<string name="ten_explaination">This is number ten</string>

我在 MainActivity 中的代码:

    Random number,number_explaination;
    int [] array_number,array_number_explaination;
    int textview_number,textview_number_explaination;
    TextView textView1,textView2;

    number = new Random();
    array_number = new int[] {R.string.one,R.string.two,R.string.three,R.string.four,R.string.five,R.string.six,R.string.seven,
            R.string.eight,R.string.nine,R.string.ten};
    textview_number = number.nextInt(array_number.length - 1);
    textView1.setText(array_number[textview_number]);

            number_explaination = new Random();
    array_number_explaination = new int[] {R.string.one_explaination,R.string.two_explaination,R.string.three_explaination,
            R.string.four_explaination,R.string.five_explaination,R.string.six_explaination,R.string.seven_explaination,
            R.string.eight_explaination,R.string.nine_explaination,R.string.ten_explaination};
    textview_number_explaination = number_explaination.nextInt(array_number_explaination.length - 1);
    textView2.setText(array_number_explaination[textview_number_explaination]);

如果我在我的 textview1 中获得 Random R.string.two 然后我将获得 R.string.two_explaination 等等，我想要的是什么。我怎样才能实现这个。抱歉我的英语不好。

Answer 1

试试这个

    Random number,number_explaination;
    int [] array_number,array_number_explaination;
    int textview_number,textview_number_explaination;
    TextView textView1,textView2;

    number = new Random();
    array_number = new int[] {R.string.one,R.string.two,R.string.three,R.string.four,R.string.five,R.string.six,R.string.seven,
            R.string.eight,R.string.nine,R.string.ten};

    array_number_explaination = new int[] {R.string.one_explaination,R.string.two_explaination,R.string.three_explaination,
            R.string.four_explaination,R.string.five_explaination,R.string.six_explaination,R.string.seven_explaination,
            R.string.eight_explaination,R.string.nine_explaination,R.string.ten_explaination};  

    textview_number = number.nextInt(array_number.length - 1);
    textView1.setText(getResources().getString(array_number[textview_number]));
    textView2.setText(getResources().getString(array_number_explaination[textview_number]));

您不需要为解释文本生成另一个随机数