java - 使用 URI 构建器构建 URL

Question

编码的 URL -

https://spreadsheets.google.com/tq?tqx=out:JSON&tq=select%20*%20where%20((A%20%3D%20201))&key=1424bS7kU8nJbHdu4QdoAFdIdWDSnmEnj2NqfMb6rPTU

解码后的 URL -

https://spreadsheets.google.com/tq?tqx=out:JSON&tq=select * where ((A= 201))&key=1424bS7kU8nJbHdu4QdoAFdIdWDSnmEnj2NqfMb6rPTU

在 URI 构建器中，我们应该使用哪个 URL 进行编码或解码？

此外，给定的代码也不起作用:-

String xyz="1424bS7kU8nJbHdu4QdoAFdIdWDSnmEnj2NqfMb6rPTU";
    String X="201";


    final String STUDENT_RECORD_URL="https://spreadsheets.google.com/tq?tqx=out:JSON&tq=select*where";
    final String Frag1 = "A";
    final String Frag2 =  "key";
    Builder builder = Uri.parse(STUDENT_RECORD_URL).buildUpon();
    builder.appendQueryParameter(Frag1,X);
    builder.appendQueryParameter(Frag2,xyz);
    String finalUri=builder.build().toString();

Answer 1

我认为您误解了您的查询参数是什么。它们都应该是您网址中的键值对。对于你的 url https://spreadsheets.google.com/tq?tqx=out:JSON&tq=select * where ((A= 201))&key=1424bS7kU8nJbHdu4QdoAFdIdWDSnmEnj2NqfMb6rPTU，构建它看起来像:

final String STUDENT_RECORD_URL="https://spreadsheets.google.com/tq";

Builder builder = Uri.parse(STUDENT_RECORD_URL).buildUpon();
builder.appendQueryParameter("txq", "out:JSON");
builder.appendQueryParameter("tq", "select * where ((A= 201))");
builder.appendQueryParameter("key", "1424bS7kU8nJbHdu4QdoAFdIdWDSnmEnj2NqfMb6rPTU");

String finalUri = builder.build().toString();

appendQueryParameter 方法将自动对您的参数进行 url 编码。