java - 解析 Json 字符串检索所有字段

标签 java android json

我一直在尝试用 volley 解析 json,不知何故我设法提取了一些数据,但我无法解析其他字段。我正在尝试做的是检查哪个用户角色是医生并将该用户仅存储到 a1 arraylist

{"user1":{"password":"******","presence":{"lastSeen":1484695229773,"status":"online"},"role":"Patient"},"user2":{"password":"******","presence":{"lastSeen":1484695229773,"status":"offline"},"role":"Doctor"}}

这是我的代码:

   public class Users extends AppCompatActivity {
    ListView usersList;
    TextView noUsersText;
    ArrayList<String> al = new ArrayList<>();
    int totalUsers = 0;
    ProgressDialog pd;
    private Firebase mRef;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.act_users);

        usersList = (ListView)findViewById(R.id.usersList);
        noUsersText = (TextView)findViewById(R.id.noUsersText);


        pd = new ProgressDialog(Users.this);
        pd.setMessage("Loading...");
        pd.show();

        String url = "https://**********.firebaseio.com/users.json";

        StringRequest request = new StringRequest(Request.Method.GET, url, new Response.Listener<String>(){
            @Override
            public void onResponse(String s) {
                doOnSuccess(s);
            }
        },new Response.ErrorListener(){
            @Override
            public void onErrorResponse(VolleyError volleyError) {
                System.out.println("" + volleyError);
            }
        });

        RequestQueue rQueue = Volley.newRequestQueue(Users.this);
        rQueue.add(request);

        usersList.setOnItemClickListener(new AdapterView.OnItemClickListener() {
            @Override
            public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
                UserDetails.chatWith = al.get(position);
                startActivity(new Intent(Users.this, Chat.class));
            }
        });






    }//oncreate ends here




    public void doOnSuccess(String s){
        try {
            JSONObject obj = new JSONObject(s);

            Iterator i = obj.keys();
            String key = "";

            while(i.hasNext()){
                key = i.next().toString();

                if(!key.equals(UserDetails.username)) {
                    al.add(key); /// here want to store only user with doctor role
//currently all users are displaying
                }

                totalUsers++;
            }

        } catch (JSONException e) {
            e.printStackTrace();
        }

        if(totalUsers <=1){
            noUsersText.setVisibility(View.VISIBLE);
            usersList.setVisibility(View.GONE);
        }
        else{
            noUsersText.setVisibility(View.GONE);
            usersList.setVisibility(View.VISIBLE);
            usersList.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, al));
        }

        pd.dismiss();
    }
}

我成功获取了根对象“user1”和“user2”,但我还想提取所有其他字段

请告诉我如何更改所有字段的代码。

EDITED

 public void doOnSuccess(String s){
        try {
            JSONObject obj = new JSONObject(s);




            Iterator i = obj.keys();
            String key = "";

            while(i.hasNext()){
                key = i.next().toString();
                JSONObject singleUser = (JSONObject) obj.get(key);
                String role = singleUser.get("role").toString();

                if(!key.equals(UserDetails.username)) {
                    if (role.equals("Doctor")) {
                       // doctors.add(keys);
                        al.add(key);
                    }

                }

                totalUsers++;
            }

        } catch (JSONException e) {
            e.printStackTrace();
        }

        if(totalUsers <=1){
            noUsersText.setVisibility(View.VISIBLE);
            usersList.setVisibility(View.GONE);
        }
        else{
            noUsersText.setVisibility(View.GONE);
            usersList.setVisibility(View.VISIBLE);
            usersList.setAdapter(new ArrayAdapter<String>(this, android.R.layout.simple_list_item_1, al));
        }

        pd.dismiss();
    }
}

最佳答案

您从用户对象中获取值如下

JSONObject user = obj.getJSONObject("user1");
String role = user.getString("role");
JSONObject presence = user.getJSONObject("presence");
String status = presence.getString("status");

关于java - 解析 Json 字符串检索所有字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41709035/

相关文章:

javascript - 我怎样才能遍历这个Javascript对象?

java - 如何使用带有 itext 的 pdf 模板导出数据集?

java - 如何处理倾向于一个apk的多个android项目

java - 将图标拖放到主屏幕

java - Genson:使用 RuntimePropertyFilter 时处理子属性

javascript - 字符串化 JavaScript 对象

java - 并非所有内容类型都支持 Spring REST Controller 内容/类型

java - 指针引用指向哪个对象?

java - 具有该位置 [5] 的参数不存在;

android - 在 android map v2 上坚持道路的位置