我有一个选项卡式 Activity 1 到 5。如果我从 3 移动到 5,然后按下后退,我想从 5 切换回 3,即按下后退,我想回到上一个选项卡。请帮忙
最佳答案
使用下面的代码来实现它。(代码也经过测试。)
1.初始化一个整数列表和一个 boolean 值;
private boolean isBackPressed = false;
private boolean isBackPressedOnce = false;
private List<Integer> tabsInBack = new ArrayList<>();
2.现在你的 onTabSelectedListener 必须是这样的
tabs.setOnTabSelectedListener(new TabLayout.OnTabSelectedListener() {
@Override
public void onTabSelected(TabLayout.Tab tab) {
if(!isBackPressed){
tabsInBack.add(tab.getPosition());}
else {
isBackPressed = false;}
}
@Override
public void onTabUnselected(TabLayout.Tab tab) {
}
@Override
public void onTabReselected(TabLayout.Tab tab) {
}
});
3(i).现在你的 onBackPressed() 函数必须是,(一个选项卡返回然后关闭)
@Override
public void onBackPressed() {
isBackPressed = true;
if (tabsInBack != null && tabsInBack.size() > 0) {
if (tabs.getSelectedTabPosition() == tabsInBack.get(tabsInBack.size() - 1)) {
tabsInBack.remove(tabsInBack.size() - 1);
}
if (tabsInBack != null && tabsInBack.size() > 0) {
tabs.getTabAt(tabsInBack.get(tabsInBack.size() - 1)).select();
tabsInBack.remove(tabsInBack.size() - 1);
} else {
super.onBackPressed();
}
} else {
super.onBackPressed();
}
}
3(ii)。现在你的 onBackPressed() 函数必须是,(返回所有选定的标签然后关闭)
@Override
public void onBackPressed() {
isBackPressed = true;
if (tabsInBack != null && tabsInBack.size() > 0) {
if (tabs.getSelectedTabPosition() == tabsInBack.get(tabsInBack.size() - 1)) {
tabsInBack.remove(tabsInBack.size() - 1);
}
if (tabsInBack != null && tabsInBack.size() > 0) {
tabs.getTabAt(tabsInBack.get(tabsInBack.size() - 1)).select();
tabsInBack.remove(tabsInBack.size() - 1);
if(isBackPressedOnce )
{
super.onBackPressed();
}
else
{
isBackPressedOnce = true;
}
} else {
super.onBackPressed();
}
} else {
super.onBackPressed();
}
}
让我知道它是否有帮助。
关于java - 如何在选项卡式 Activity 中切换回上一个选项卡,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47551172/