Android:在计算机控制的 UI 更改期间更新屏幕

Question

我已经检查了这里提出的其他问题，但没有成功实现解决方案。我的应用程序使用控件，而不是在 Canvas 上绘图。基本上这总结了我的问题:-

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    btn1 = (ToggleButton) findViewById(R.id.btn1);
    btn2 = (ToggleButton) findViewById(R.id.btn2);
    btn3 = (ToggleButton) findViewById(R.id.btn2);
    btn4 = (ToggleButton) findViewById(R.id.btn4);
    btn5 = (ToggleButton) findViewById(R.id.btn5);
    btn6 = (ToggleButton) findViewById(R.id.btn6);
    btn7 = (ToggleButton) findViewById(R.id.btn7);
 //blah blah blah
    btn1.requestFocus();
    wait(100);
    btn2.requestFocus();
    wait(100);
    btn3.requestFocus();
    wait(100);
    btn3.setChecked(true);
    wait(100);
    btn4.requestFocus();
    wait(100);
    btn4.setChecked(true);
    wait(100);
    btn5.requestFocus();
    wait(100);
    btn6.requestFocus();
    wait(100);
    btn6.setChecked(true);
    wait(100);
    btn7.requestFocus();
    wait(100);
 //etc
}

要点是计算机动画移动到按钮并检查它们，以便用户可以看到它在做什么。所以，我的问题是，暂停 100 毫秒并更新屏幕和焦点的 wait() 方法中发生了什么？非常感谢任何帮助，乔纳森干杯。

解决方案适用，谢谢 Andrew :)

int timerCounterInterval = 0;

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    final ToggleButton btn1 = (ToggleButton) findViewById(R.id.btn1);
    final ToggleButton btn2 = (ToggleButton) findViewById(R.id.btn2);
// more btns
    timerCounterInterval = 0; //reset, for each pass of automation
    setFocus(btn1);
    setFocus(btn2);
    setChecked(btn2);
// tidy up
    timerCounterInterval++;
    new Handler().postDelayed(new Runnable() { 
        public void run() {
            btn2.clearFocus(); //whatever button that had the focus last
            }
    }, 100*(timerCounterInterval));
// etc - note any code from here will execute *before* the above timer
}   

public void setFocus(final ToggleButton btn) {
    timerCounterInterval++;
    new Handler().postDelayed(new Runnable() { 
        public void run() {
            btn.setFocusableInTouchMode(true); //eww, messy i know
            btn.requestFocus();
            btn.setFocusableInTouchMode(false); 
        } 
    }, 100*timerCounterInterval);
}

public void setChecked(final ToggleButton btn) {
    timerCounterInterval++;
    new Handler().postDelayed(new Runnable() { 
        public void run() {
            btn.setChecked(true);
        } 
    }, 100*timerCounterInterval);
}

希望这对其他人有帮助!

Answer 1

我强烈建议您查看 Handle对象，特别是 postDelayed方法。这样您就可以将所有内容都保留在 UI 线程上，而不会导致线程实际上被绑定(bind)在动画方法中。这也可以防止 Activity 发出可怕的“此应用程序未响应”消息。

事实上，只需将对控件的 setter 的调用包装在一个 runnable 中并将它们传递给 postDelayed 就足以更新 GUI 控件。

[更新] 作为根据您的评论的示例，您可以尝试这样的事情。我还没有真正测试过这个，但我认为这个想法仍然存在......

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    final ToggleButton btn1 = (ToggleButton) findViewById(R.id.btn1);
    final ToggleButton btn2 = (ToggleButton) findViewById(R.id.btn2);
    // more btns

    Handler handler = new Handler();

    /* tell the handler run these bits after 1 sec, 2 sec, 3 sec, ect... */
    handler.postDelayed(new Runnable() { void run () { btn1.requestFocus(); } }, 1000);
    handler.postDelayed(new Runnable() { void run () { btn2.requestFocus(); } }, 2000);
    handler.postDelayed(new Runnable() { void run () { btn2.setChecked(true); } }, 3000);
}