java - 使用 JSON 的登录表单

Question

我正在尝试通过连接到我的数据库并验证用户名和密码来制作登录表单，我正在使用 JSON 方法

 public class LoginActivity extends Activity {
 JSONParser jParser = new JSONParser();
 private static String url_login = "http://192.168.1.81:80get_all_usernames.php";
 JSONArray admin = null;
 int i;


@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.adminlogin);
}


 public void enter(View v)
 {

      TextView user= (TextView) findViewById (R.id.user);
      TextView pass= (TextView) findViewById (R.id.pass);
      CharSequence usr=  user.getText();
      CharSequence pwd=pass.getText();
      Log.i("",""+usr);
      Log.i("",""+pwd);
      ArrayList<NameValuePair> param = new ArrayList<NameValuePair>();
     JSONObject json = jParser.makeHttpRequest(url_login, "GET",param);

      Log.i("","fjefejjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj");
     try{
       int success = json.getInt("success");

       if(success == 1){
    admin = json.getJSONArray("admin");
        for(i=0;i<admin.length();i++){
        final JSONObject c = admin.getJSONObject(i);
        String real_user=c.getString("username");
        String real_password= c.getString("password");
            if(usr==real_user && pwd==real_password)
            {
     Log.i("success","login sucessfull-----------------------");
        }
     else{
       Log.i("fail","Login failed ----------------------------------");
         }
     }}
    }catch(Exception e){
      }
   }

      }

它一直在该行返回错误: JSONObject json = jParser.makeHttpRequest(url_login, "GET",param); 有人可以帮我吗？

先谢谢你， 拉尔夫

Answer 1

您的网址有误:

http://192.168.1.81:80get_all_usernames.php

应该是:

http://192.168.1.81:80/get_all_usernames.php

此外，对于 http，您无需指定端口 80。这是默认端口。